我可以将@Where注释与@ManytoOne关联一起使用吗?

时间:2019-06-26 10:45:04

标签: mysql spring hibernate jpa bidirectional

EER Diagram

我不是Spring,JPA,Hibernate或MySql的专家。 但是,我正在使用所有支持RESTful调用的Web服务。 我正在用Spring构建一个商店管理应用程序后端。 我目前的实体是StoreModel,StoreUserModel,StoreUserRoleModel和StoreUserAuthModel。

我之间建立了双向关系(OneToMany和ManyToOne) StoreModel-StoreUserAuthModel, StoreUserMode-StoreUserAuthModel和 StoreUserRoleMode-StoreUserAuthModel。

尽管StoreUserAuthModel中有外键字段storeid,roleid和userid,但我不希望使用外键约束。

现在,所有四个表都具有isdeleted列,以实现软删除。 我懒洋洋地取缔这些协会。但是,无论何时我查询关联,我都不希望被软删除的值。

我想知道是否可以在StoreUserAuthModel实体中同时使用@Where注释和@ManyToOne注释?

问题与How to use @Where in Hibernate不同,因为我的问题是与ManyToOne批注有关,而我对OneToMany使用了where批注

@Entity
@Table(name = "store")
public class StoreModel {

    @NotBlank
    private String name;

    @NotBlank
    private String address;

    @NotBlank
    private String city;

    @NotBlank
    private String phone;


    @JsonIgnore
    @OneToMany(fetch = FetchType.LAZY)
    @JoinColumn(name = "storeid", foreignKey = @ForeignKey(name="none", value = ConstraintMode.NO_CONSTRAINT ))
    @Where(clause="isdeleted = 0")
    private List<StoreUserAuthModel> authList = new ArrayList<StoreUserAuthModel>();


    ...
}

@Entity
@Table(name = "storerole")
public class StoreRoleModel {

    @NotBlank
    private String name;

    @NotBlank
    private Integer rolehierarchy;

    @JsonIgnore
    @OneToMany(fetch = FetchType.LAZY)
    @JoinColumn(name = "roleid", foreignKey = @ForeignKey(name="none", value = ConstraintMode.NO_CONSTRAINT ))
    @Where(clause="isdeleted = 0")
    private List<StoreUserAuthModel> authList = new ArrayList<StoreUserAuthModel>();

    ...


}

@Entity
@Table(name = "storeuser")
public class StoreUserModel{

    @NotBlank
    @Column(unique = true)
    private String username;

    @Email
    @Column(unique = true)
    private String useremail;

    @JsonIgnore
    @OneToMany(fetch = FetchType.LAZY)
    @JoinColumn(name = "userid", foreignKey = @ForeignKey(name="none", value = ConstraintMode.NO_CONSTRAINT ))
    @Where(clause="isdeleted = 0")
    List<StoreUserAuthModel> userAuthList = new ArrayList<StoreUserAuthModel>();

    ...

}

@Entity
@Table(name = "storeuserauth", 
        uniqueConstraints = @UniqueConstraint(columnNames = {"storeid", "roleid", "userid"}))
public class StoreUserAuthModel {

    @NotNull
    Long storeid;

    @NotNull
    Long roleid;

    @NotNull
    Long userid;

    // Using @where to filter out the soft deleted storeuser
    @JsonIgnore
    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(name="userid", foreignKey = @ForeignKey(name="none",  value = ConstraintMode.NO_CONSTRAINT ),insertable = false, updatable = false )
    @Where(clause="isdeleted = 0")
    private StoreUserModel storeuser;

    // Using @where to filter out the soft deleted store
    @JsonIgnore
    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(name="storeid", foreignKey = @ForeignKey(name="none",  value = ConstraintMode.NO_CONSTRAINT ),insertable = false, updatable = false )
    @Where(clause="isdeleted = 0")
    private StoreModel store;

    // Using @where to filter out the soft deleted role
    @JsonIgnore
    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(name="roleid", foreignKey = @ForeignKey(name="none",  value = ConstraintMode.NO_CONSTRAINT ),insertable = false, updatable = false )
    @Where(clause="isdeleted = 0")
    private StoreRoleModel role;

    ...


}


// In the controller, Following code shows how I plan to use

    Optional<StoreUserModel> aUser = storeUserRepository.findByUseremailAndIsdeleted(zUserMail), 0);
    if(aUser.isPresent()) {
        // The user was found!!!

        // Testing...
        // Getting the User Auth List (that will filter out the soft deleted auths)
        List<StoreUserAuthModel> authList = aUser.get().getUserAuthList();
        for(StoreUserAuthModel auth :authList) {
            StoreModel store = auth.getStore();
            // here both soft deleted store as well as normal stores are shown.
            // ie where clause  on  store relation is not working!!

            logger.debug("Store is "+store.getName());
        }


    }

...

现在,所有与ID匹配的商店行都在列表中。 预期结果也应该在where子句中应用

我打开了休眠5.3.9的日志记录 触发选择查询时没有where子句

1 个答案:

答案 0 :(得分:0)

@Where注释对ToOne关系没有影响。但是,除了在引用中添加@Where之外,您还可以在实体上使用@Where:

@Where(clause="isdeleted = 0")
@Entity
@Table(name = "storerole")
public class StoreRoleModel {

这样,Hibernate将不会加载StoreRoleModel的已删除实体。

相关问题