Question

我有一个包含多值字段（存款，Tax1和tax2）的sql表，如下所示：

ID   Account_Number    Plan       Deposits       Tax1            Tax2

10   123456            PRINC10      4;4       4256.45;1567.45  4256.45;1567.45


11   123456            KrINC11      4;4       4256.45;1567.45  4256.45;1567.45

我已使用来自SQL Servercentral.com的DelimiterSplit8K表值函数分隔了多值字段。

我用来将多值字段分开以分隔行的代码如下：

 Select [ID], [account_number], [Plan], [Deposits], [Tax1], [Tax2]
 From MVTable
 Cross apply dbo.DelimitedSplit8K(MVTable.Deposits, ';') as Depositlist
 Cross apply dbo.DelimitedSplit8K(MVTable.Tax1, ';') as Tax1List
 Cross apply dbo.DelimitedSplit8K(MVTable.Tax2, ';') as Tax2List
  `enter code here`Where DepositList.Itemnumber = Tax1list.itemnumber
  and Depositlist.itemnumber = Tax2list.itemnumber

但是我收到的数据有些重复

ID   account_number     Plan     Deposits   Tax1         Tax2 

10   123456             PRINC10    4        4256.45     4256.45

10   123456             PRINC10    4        1567.45     1567.45

11   123456             KrINC11    4        4256.45     4256.45

11   123456             KrINC11    4        1567.45     1567.45

期望的结果应如下所示，我们只希望为每个帐号/ id字段和Tax1和Tax2字段分别分配一个计划字段。

ID   account_number     Plan     Deposits   Tax1         Tax2 

10   123456             PRINC10    4        4256.45     4256.45

11   123456             KrINC11    4        1567.45     1567.45

Answer 1

我建议使用另一种分割值的方法：

with cte as (
      select id, account_number, plan,
             convert(varchar(max), left(deposits, charindex(';', deposits + ';') - 1)) as deposit,
             convert(varchar(max), left(tax2, charindex(';', tax2 + ';') - 1)) as tax1,
             convert(varchar(max), left(tax2, charindex(';', tax2 + ';') - 1)) as tax2,
             convert(varchar(max), stuff(deposits, 1, charindex(';', deposits + ';'), '')) as deposit_rest,
             convert(varchar(max), stuff(tax1, 1, charindex(';', tax1 + ';'), '')) as tax1_rest,
             convert(varchar(max), stuff(tax2, 1, charindex(';', tax2 + ';'), '')) as tax2_rest
      from t
      union all
      select id, account_number, plan,
             convert(varchar(max), left(deposit_rest, charindex(';', deposit_rest + ';') - 1)) as deposit,
             convert(varchar(max), left(tax2_rest, charindex(';', tax2_rest + ';') - 1)) as tax1,
             convert(varchar(max), left(tax2_rest, charindex(';', tax2_rest + ';') - 1)) as tax2,
             convert(varchar(max), stuff(deposit_rest, 1, charindex(';', deposit_rest + ';'), '')) as deposit_rest,
             convert(varchar(max), stuff(tax1_rest, 1, charindex(';', tax1_rest + ';'), '')) as tax1_rest,
             convert(varchar(max), stuff(tax2_rest, 1, charindex(';', tax2_rest + ';'), '')) as tax2_rest
       from cte
       where deposit_rest <> ''
      )
select *
from cte;

Here是db <>小提琴。

Answer 2

如果您需要每个acc_number / id一个计划，而不关心tax1和tax2，那么您可以使用它，

select id, account_number, [plan],
convert(varchar(max), left(deposits, charindex(';', deposits) - 1)) as deposit,
convert(varchar(max), left(tax2, charindex(';', tax2) - 1)) as tax1,
convert(varchar(max), left(tax2, charindex(';', tax2) - 1)) as tax2
from ##t

输出看起来像

id  account_number  plan    deposit tax1        tax2
10  123456          PRINC10     4   4256.45     4256.45
11  123456          KrINC11     4   4256.45     4256.45

从表中选择唯一记录

2 个答案: