Question

我正在设置一个应用程序以接受动态的多部分文件上传表单。

我为上传的类型和扩展名添加了条件if规则。要使有条件的满足被接受并存储在DB中，对于空的发布文件应被忽略，而其余的则应被拒绝。

        $allowedExts = array("gif", "jpeg", "jpg", "png", "pdf");
        $jumlah_syarat = count($_FILES);
        $forwardexts = array("");

        $diam = array();
        $tolak = array();
        foreach ($_FILES as $y => $file){
            $ext_file = strtolower(end(explode('.',$file['name'])));
            if (($file["type"] == "image/gif")
            || ($file["type"] == "image/jpeg")
            || ($file["type"] == "image/jpg")
            || ($file["type"] == "image/pjpeg")
            || ($file["type"] == "image/x-png")
            || ($file["type"] == "image/png")
            || ($file["type"] == "application/pdf")
            && in_array($ext_file, $allowedExts)) {
                $tmpfile = $file['tmp_name'];
                $namafile =  $noPendaf."-".$idPendaf."-".$y.".".$ext_file;
                $kefile = $path.$namafile;
                $syarats['idsyarat'][] = $y;
                $syarats['filesyarat'][$y] = $namafile;
                move_uploaded_file($tmpfile,$kefile);
            } elseif(($file["type"] == "") && in_array($ext_file, $forwardexts)){
                array_push($diam, 1);
            } else{
                array_push($tolak, 1);
            }
        }

对于上面的代码，预期结果是等待所有上传的文件并循环进入foreach，然后进行过滤。但是，在文件完全发送（上载）到服务器之前，我总是得到$ tolak得到array_push 1

Answer 1

在文件上传后添加此代码，以检查文件是否上传

$file_pointer = '';//here you need to pass your absolute path
if (file_exists($file_pointer)) {
    echo "The file $file_pointer exists";
}else {
    echo "The file $file_pointer does not exists";
}

如何检查文件是否成功上传

1 个答案: