Question

DELETE FROM ...不起作用。正确的参数将传递给函数。没有错误返回。

我试图修改路由，通过POST和GET传递参数，并且在胎儿的位置哭了很多。

conn = mysql.connect()
cursor = mysql.connect().cursor()
cursor.execute("SELECT * FROM food_on_the_table WHERE table_id = %s", table_id) 
food_on_the_table = cursor.fetchall()
records = cursor.fetchall() 
cursor.execute("DELETE FROM food_on_the_table WHERE row_id = %s", row_id)   
conn.commit()
result = cursor.rowcount
message = "rows affected " + str(result)    
cursor.close()

没有行从数据库中删除。 row_i是正确的，rows affected = 1是预期的。

Answer 1

尝试一下

try:
    conn = mysql.connect()
    with conn.cursor() as cursor:
        cursor.execute("SELECT * FROM food_on_the_table WHERE table_id = %s", table_id)
        food_on_the_table = cursor.fetchall()
        records = food_on_the_table 
    with conn.cursor() as cursor:
        cursor.execute("DELETE FROM food_on_the_table WHERE row_id = %s", row_id)

    conn.commit()

finally:
    conn.close()

为什么在PYTHON中的SQL查询中删除不提交数据库中的更改？

1 个答案: