Vert.x请求处理程序并阻止数据库查询

时间:2019-07-05 12:26:57

标签: java reactive-programming rx-java2 vert.x

如何在vert.x中正确翻译这段代码?

通常,在春季或带有模板引擎的简单sevlet中,我会这样做,以输出html响应

function test(request, response) {
  templatecontext tc = getContext();

  init conditions

  if (condition1) {
    retrieve data from db ({
      asyncresult -> {
        tc.put("data1", data1)
      })
  } else if (condition2) {
    other code

    if (condition 2.1) {        
      retrieve data from db ({
        asyncresult -> {
          tc.put("data2", data2)
        })
    }
  }

  get other data from db and put in context
  template.eval("templatefile", tc)
  write to response
}

问题是,从数据库中检索数据是asyncresult的处理程序,因此我不能授予模板评估是使用data1或data2进行的,因为检索异步时不会掉入回调地狱。

我不太了解rxjava2,但是我觉得我想用勺子杀死豆子。

1 个答案:

答案 0 :(得分:1)

您可以使用futurescomposition。请参见vertx-examples回购中的ComposeExample

public class ComposeExample extends AbstractVerticle {    

  @Override
  public void start() throws Exception {
    Future<String> future = anAsyncAction();
    future.compose(this::anotherAsyncAction)
      .setHandler(ar -> {
        if (ar.failed()) {
          System.out.println("Something bad happened");
          ar.cause().printStackTrace();
        } else {
          System.out.println("Result: " + ar.result());
        }
      });
  }

  private Future<String> anAsyncAction() {
    Future<String> future = Future.future();
    // mimic something that take times
    vertx.setTimer(100, l -> future.complete("world"));
    return future;
  }

  private Future<String> anotherAsyncAction(String name) {
    Future<String> future = Future.future();
    // mimic something that take times
    vertx.setTimer(100, l -> future.complete("hello " + name));
    return future;
  }
}
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