Question

我之前曾问过一个问题，但是我对查询的理解太深了，以至于我无法采用该解决方案并将其应用于我的原始查询。因此，我正在再次尝试。

我有一个CTE，我需要将其转换为MySQL 5.6的“常规”查询。对于该项目，我们不会很快升级到MySQL 8或MariaDB 10.x。

查询如下：

        WITH currentUserPermissions (permissionID, action, level) AS (
            SELECT
                p.permissionID,
                p.action,
                CASE WHEN p.level = 1 AND rp.level = 1 THEN 2 ELSE COALESCE(rp.level, 0) END AS level
            FROM user_org_sport op
                JOIN rolePermissions rp ON op.roleID = rp.roleID AND op.orgID = rp.orgID
                JOIN permissions p ON p.permissionID = rp.permissionID
            WHERE op.userProfileID = :userID
                AND op.orgID = :orgID
                AND p.systemFlag = 0
        )

        SELECT action, level
        FROM currentUserPermissions

        UNION

        SELECT p.action, p.level
        FROM permissions p
        WHERE p.systemFlag = -1

        UNION

        SELECT p.action, 0 AS level
        FROM permissions p
            LEFT JOIN currentUserPermissions cup ON cup.action = p.action
        WHERE cup.action IS NULL
            AND p.systemFlag = 0

我不是数据库专家（主题专家），所以我们将不胜感激。由于我缺乏数据库经验，所以无法对查询应用上一个答案。

Answer 1

对于每个引用，您都需要复制一次CTE：

SELECT action, level
FROM (
    SELECT
        p.permissionID,
        p.action,
        CASE WHEN p.level = 1 AND rp.level = 1 THEN 2 ELSE COALESCE(rp.level, 0) END AS level
    FROM user_org_sport op
    JOIN rolePermissions rp ON op.roleID = rp.roleID AND op.orgID = rp.orgID
    JOIN permissions p ON p.permissionID = rp.permissionID
    WHERE op.userProfileID = :userID
      AND op.orgID = :orgID
      AND p.systemFlag = 0
) x

UNION

SELECT p.action, p.level
FROM permissions p
WHERE p.systemFlag = -1

UNION

SELECT p.action, 0 AS level
FROM permissions p
LEFT JOIN (
    SELECT
        p.permissionID,
        p.action,
        CASE WHEN p.level = 1 AND rp.level = 1 THEN 2 ELSE COALESCE(rp.level, 0) END AS level
    FROM user_org_sport op
    JOIN rolePermissions rp ON op.roleID = rp.roleID AND op.orgID = rp.orgID
    JOIN permissions p ON p.permissionID = rp.permissionID
    WHERE op.userProfileID = :userID
      AND op.orgID = :orgID
      AND p.systemFlag = 0
) cup ON cup.action = p.action
WHERE cup.action IS NULL
  AND p.systemFlag = 0

当然，MySQL 5.x方式为查询增加了冗余，并且由于CTE可能需要计算两次而不是一次而变得更慢。

还原CTE（公用表Expressin）

1 个答案: