模拟调用服务方法时

时间:2019-07-11 11:24:49

标签: java testing junit mocking mockito

我有一个SpringBoot应用程序,其中进行了一些测试。我有这个Junit测试:

和测试:

        public class FindHotelDataRequestTransformerTest {


            @Autowired
            private BackendHotelService backendHotelService;

            private FindHotelDataRequestTransformer transformer;

            @Before
            public void setUp() {
                transformer = new FindHotelDataRequestTransformer( backendHotelService);
            }

        @Test
        public void theTest() {
            mock(BackendHotelService.class);
when(transformer.getHotelApplicationName()).thenReturn("NameMocked");
...

        }
    }

这是基于以下类别:

public abstract class HotelDataRequestTransformer {



    private final BackendCredentialsService backendCredentialsService;

    public HotelDataRequestTransformer(BackendCredentialsService backendCredentialsService) {
        this.backendCredentialsService = backendCredentialsService;
    }

    public String getHotelApplicationName() {
        return backendCredentialsService.getHotelApplicationName();
    }


}




    @Component
    public class FindHotelDataRequestTransformer extends HotelDataRequestTransformer {


        public FindHotelDataRequestTransformer(BackendHotelService backendHotelService) {
            super (backendHotelService);
        }
    ..
    }

但是当我运行测试时,我在行中得到了一个空指针

return backendCredentialsService.getHotelApplicationName();

所以看来Mocking.when不起作用

2 个答案:

答案 0 :(得分:2)

从模拟本身而不是被测类返回

backendHotelService = mock(BackendHotelService.class); // also use the mock created :)
when(backendHotelService.getHotelApplicationName()).thenReturn("NameMocked");

答案 1 :(得分:0)

transformer不是您要创建新转换器的模拟对象。

backendHotelService是模拟对象。

尝试: when(backendHotelService.getHotelApplicationName()).thenReturn("NameMocked");

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