Question

我只是尝试使用malloc，代码运行良好，但是Visual Studio却给我带来了问题。这是您应该怎么做的事情，还是我做错了事？

警告直接出现在行上：

chadley->name = "chadley"

#include <stdio.h>
#include <stdlib.h>


typedef struct {
    int age;
    char *name;
} Person;


int main()
{
    Person bradley;
    bradley.name = "bradley";
    bradley.age = 2334444;

    Person *chadley = malloc(sizeof(Person));
    chadley->name = "chadley";
    chadley->age = 234;

    printf("Person object %s of age %d", chadley->name, chadley->age);
}

错误代码：取消引用NULL指针“查德利”

Answer 1

Person *可以为空指针。它是指值，而不是类型。

如果无法成功分配内存，则malloc将返回一个NULL值。使用前，应始终检查从malloc返回的值。

您可以执行以下操作来检查返回的指针是否有效：

Person *chadley = malloc(sizeof(Person));

if (!chadley) {
    /* The allocation failed, don't continue. */
    return 1;
}

chadley->name = "chadley";
chadley->age = 234;

Answer 2

#include <stdio.h>
#include <stdlib.h>


typedef struct {
    int age;
    char *name;
} Person;


int main()
{
    Person bradley;
    bradley.name = "bradley";
    bradley.age = 2334444;

    Person *chadley = malloc(sizeof(Person));
    if (chadley == NULL) return 1;
    chadley->name = "chadley";
    chadley->age = 234;
    printf("Person object %s of age %d", chadley->name, chadley->age);
}

工程谢谢！

Visual Studios给我取消引用空指针警告

2 个答案: