在Accord.NET中具有已知固定截距的线性回归

时间:2019-07-12 07:37:05

标签: vb.net linear-regression accord.net

我根据此页面http://accord-framework.net/docs/html/T_Accord_Statistics_Models_Regression_Linear_SimpleLinearRegression.htm使用Accord.NET计算线性回归的斜率和截距

我想设置一个固定的截距值,以便Accord仅能预测斜率。我可以在Accord.NET中做那件事吗?

Dim inp(10), opt(10) As Double
inp = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
opt = {2, 4, 6, 8, 10, 12, 14, 16, 18, 20}

Dim ols As New OrdinaryLeastSquares
Dim reg As New SimpleLinearRegression

reg.Intercept = 4 'no effect, how can we set the intercept value?
reg = ols.Learn(inp, opt)

Dim hsl As String
hsl = "y=" + reg.Slope.ToString + "X+" + reg.Intercept.ToString

1 个答案:

答案 0 :(得分:0)

设置ols.UseIntercept = False,将所需的截距值添加到每个opt值,然后运行ols.Learn()。将为您想要的截距计算出结果Slope

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