如何将一列与其余各列按同一列的值分组。
我有一个表，其中包含进入退出场景，在该场景中，具有1个进入条形码的1个toll_id和方法1的车辆进入可以退出其他toll_id的休息，并且那条码存储在exit_barcode和方法2中。
table name paid_vehicle
-----------------------------------------------------------------------
toll_id | vehicletype | entry_barcode | exit_barcode | way |
-----------------------------------------------------------------------
81 | car | asdfghjk |0 |1 |
-----------------------------------------------------------------------
83 | bus | qwertyu |0 |1 |
-----------------------------------------------------------------------
82 | truck | dfghfgsd |poiuyt |2 |
-----------------------------------------------------------------------
84 | hcm | sdfgsdfg |lkjhg |2 |
-----------------------------------------------------------------------
86 | osv | zxcvb |0 |1 |
-----------------------------------------------------------------------
81 | bus | asdf |0 |1 |
-----------------------------------------------------------------------
82 | car | dfghghfg |asdfghjk |2 |
-----------------------------------------------------------------------
89 | bus | dfhgkjhd |qwertyu |2 |
-----------------------------------------------------------------------
88 | truck | poiuyt |0 |1 |
-----------------------------------------------------------------------
87 | hcm | lkjhg |0 |1 |
-----------------------------------------------------------------------
87 | osv | sdfgsdfg |zxcvb |2 |
-----------------------------------------------------------------------
89 | bus | dfolfgpkg |asdf |2 |
-----------------------------------------------------------------------
81 | car | jhfkggtg |asdfghjk |2 |
-----------------------------------------------------------------------
现在我想找到 我从1开始进入其他条形码的数量。
select * from paid_vehicle where way='2'
and exit_barcode not in(select entry_barcode from paid_vehicle where toll_id='81' and way='1' AND entry_barcode!='');
toll_id | exit_toll_id | count
------------------------------------
81 | 82 | 900
------------------------------------
81 | 83 | 4500
------------------------------------
81 | 84 | 9050
------------------------------------
81 | 85 | 7910
答案 0 :(得分：0)
您可以尝试加入进入和退出条形码
select t.tool_id, t.exit_toll_id, count(*) count
from (
select a.tool_id , a.entry_barcode, b.tool_id, exit_toll_id b.exit_barcode
from paid_vehicle a
left join paid_vehicle b on a.entry__barcode = b.entry_barcode
)
group by t.tool_id, t.exit_toll_id
order by t.tool_id, t.exit_toll_id