我的猫鼬恋爱关系有什么问题?

时间:2019-07-15 13:43:01

标签: node.js mongodb mongoose nosql relationship

我正在学习猫鼬关系,并陷入了这个问题...有人告诉我我在哪里错了..?并且有更好的方法做到这一点吗?

Employee.js

const mongoose = require("mongoose");
const { departmentSchema, addDepartment } = require("./Departments");

const schema = new mongoose.Schema();

const employeeModel = mongoose.model("Employee", {
  Name: { type: String, required: true, minlength: 5, maxlength: 50 },
  Department: departmentSchema
});

async function addEmployee(Employee, Department, Language, Framework) {
  const result = await new employeeModel({
    ...Employee,
    Department: addDepartment(Department, Language, Framework)
  });
  return await result.save();
}

Department.js

const mongoose = require("mongoose");
const { languageSchema, addLanguage } = require("./Language");

const departmentSchema = new mongoose.Schema({
  Depart: { type: String, required: true, minlength: 5, maxlength: 50 },
  Languages: languageSchema
});

const DepartmentModel = mongoose.model("Department", departmentSchema);

async function addDepartment(Department, Language, Framework) {
  const result = await new DepartmentModel({
    ...Department,
    Languages: addLanguage(Language, Framework)
  });
  return await result.save();
}

module.exports = {
  departmentSchema,
  addDepartment
};

Language.js

const mongoose = require("mongoose");
const { frameworkSchema, addFramework } = require("./Frameworks");

const languageSchema = new mongoose.Schema({
  Language: { type: String, required: true },
  Framework: [frameworkSchema]
});

const languageModel = mongoose.model("Language", languageSchema);

async function addLanguage(Language, Framework) {
  const result = await new languageModel({
    ...Language,
    Framework: addFramework(Framework)
  });
  return await result.save();
}

module.exports = {
  languageSchema: languageSchema,
  addLanguage
};

Framework.js

const mongoose = require("mongoose");

const frameworkSchema = new mongoose.Schema({
  Name: { type: String, required: true, minlength: 4, maxlength: 50 },
  Version: { type: String, required: true, minlength: 1, maxlength: 50 }
});

const frameworkModel = mongoose.model("Framework", frameworkSchema);

async function addFramework(Framework) {
  const result = await new frameworkModel(...Framework);
  return await result.save();
}

module.exports = {
  frameworkSchema,
  addFramework
};

来自Framework.js的错误

Found non-callable @@iterator

我想做的是

  1. 员工->
  2. 名称
  3. 部门->
  4. 出发
  5. 语言->
  6. 语言名称
  7. 框架->
  8. 框架名称
  9. 框架版本

每个->代表一个新对象(集合)

我知道对于像我这样的新手来说有点复杂... 我是MySql数据库用户,我喜欢它,但现在我正试图掌握NoSql ...

先谢谢您了:)

2 个答案:

答案 0 :(得分:0)

我将向您展示一个示例: 假设您已经具有 employSchema 了:

const {Schema} = mongoose;
const employeeModel = mongoose.model("Employee", new Schema({
  Name: { type: String, required: true, minlength: 5, maxlength: 50 },
  Department: {type: Schema.Types.ObjectId, ref: "Department"}
}));

在上述模型中,我使用 ref 属性通过 ObjectId 连接到部门模型(这意味着“部门”集合中的“ _id”属性)。

例如:您将像这样创建一个新的employeeModel:

let newEmployee = new employeeModel("Employee Name", Department ID here).

您绝对相反或为他人做。 并且您需要使用 .populate()函数来查询数据库。 示例:

employModel.find({}).populate("Department").exec(callback what you want to do);

您可以在以下位置阅读正式文档:https://mongoosejs.com/docs/populate.html

答案 1 :(得分:0)

一如既往地解决了错误:p

错误是由于Framework.js中的传播运算符(...)

const result = await new frameworkModel(...Framework);

即使有人可以告诉我这样做的更好方法,也将不胜感激。

This is what I was trying to achieve

谢谢大家。

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