PDO返回1而不是返回db值

Question

PDO返回1而不是返回db值

<?php
$dados = $conexao_pdo->prepare('SELECT name, surname, profile_description, verified FROM users WHERE username = ?');
$dados->bindParam(1, $user_logged);
$dados->execute();

if ($dados->rowCount() > 0) {
 $campodb = $dados->fetch(PDO::FETCH_OBJ);
 $user_logged_name =  $campodb->name;
 $user_logged_surname =  $campodb->surname;
 $user_logged_profile_description =  $campodb->profile_description;
 $user_logged_verified = $campodb->verified;


} else {
$user_logged_name =  "";
$user_logged_surname =  "";
$user_logged_profile_description = "";
$user_logged_verified = "";


}


?>

当我回显$user_logged_name时，它向我返回1，而不是数据库中的用户名，为什么？

Answer 1

您尝试了一段时间吗？

<?php
$dados = $conexao_pdo->prepare('SELECT name, surname, profile_description, verified FROM users WHERE username = ?');
$dados->bindParam(1, $user_logged);
$dados->execute();

if ($dados->rowCount() > 0) {
 //$campodb = $dados->fetch(PDO::FETCH_OBJ);
 while ($campodb = $dados->fetch(PDO::FETCH_OBJ)) {
 $user_logged_name =  $campodb->name;
 $user_logged_surname =  $campodb->surname;
 $user_logged_profile_description =  $campodb->profile_description;
 $user_logged_verified = $campodb->verified;
 }
} else {
$user_logged_name =  "";
$user_logged_surname =  "";
$user_logged_profile_description = "";
$user_logged_verified = "";


}


?>