我正在尝试几天以更改bash脚本中命令的颜色输出。我尝试了一些工作流程陷阱,但没有成功。唯一起作用的部分是这段代码:
#!/bin/bash
GRN='\e[32m'
CYN='\e[36m'
END='\e[0m'
echo -e "${GRN}Formating Root partition ..${END}"
echo -e "${CYN}"
(set -x ; mkfs.ext4 -L Root -m 5 /dev/sda2) | GREP_COLOR='49;38;5;007' grep --color=always '.*'
echo -e "${END}"
echo -e "${GRN}Formating Home partition ..${END}"
...
是否有更好的方法来做到这一点。谢谢。
我想要的是这个
Formating Root partition .. <= Green
mkfs.ext4 -L Root -m 5 /dev/sda2 <= Cyan
mke2fs 1.45.2 (27-May-2019) <= Grey
Creating filesystem with 9175040 4k blocks and 2293760 inodes <= Grey
Filesystem UUID: ... <= Grey
... <= Grey
Formating Home partition .. <= Green
答案 0 :(得分:0)
您可以使用在Mac和ubuntu上经过测试的以下脚本。
每个函数接受两个参数,
private void Button2_Click_1(object sender, EventArgs e)
{
c1 = JsonConvert.DeserializeObject<Class1>(File.ReadAllText("path.txt"));
Console.WriteLine("Current Status of Flag1: "+c1.flag);
Console.WriteLine("Current Status of Flag2: " + c1.flag2);
}
green "will print green"
bash脚本
red "will print Free space in red:" "free -m" free -m