我有两个表，其布局如下：
表A
|---------------------|-------------------------------------------------------------------------------------------|
| name | info |
|---------------------|-------------------------------------------------------------------------------------------|
| 1 | Dark Magician is a normal monster. It can be used with cards such as Dark Magician Girl. |
| 2 | Blue-Eyes White Dragon is a normal dragon monster. Dragon Capture Jar counters this card.|
|---------------------|-------------------------------------------------------------------------------------------|
表B
|--------------------- |
| name |
|----------------------|
|Dark Magician |
|Dark Magician Girl |
|Blue-Eyes White Dragon|
|Dragon Capture Jar |
|----------------------|
所以我正在将tablea.info与tableb.name进行比较，如果找到匹配项，我想用<a href="/name">name</a>替换匹配的名称
对于表A ，我的预期输出将是这样的：
|---------------------|-------------------------------------------------------------------------------------------------------------------------------------------------------------------|
| name | info |
|---------------------|-------------------------------------------------------------------------------------------------------------------------------------------------------------------|
| 1 | <a href="/Dark Magician">Dark Magician</a> is a normal monster. It can be used with cards such as <a href="/Dark Magician Girl">Dark Magician Girl</a>. |
| 2 | <a href="/Blue-Eyes White Dragon">Blue-Eyes White Dragon</a> is a normal dragon monster. <a href="/Dragon Capture Jar">Dragon Capture Jar</a> counters this card.|
|---------------------|-------------------------------------------------------------------------------------------------------------------------------------------------------------------|
我不确定这样做的最佳途径是什么。
我认为我将tableb.name与tableb.info进行了比较，但是我在更新部分方面感到苦恼。
我在想更换吗？所以像这样：
REPLACE(ta.info,'%Dark Magician%','%<a href="/Dark Magician">Dark Magician</a>%')
最好的解决办法的建议。