Question

我尝试通过发布JSON插入一些数据，但我不知道为什么，它返回一条错误消息，提示字段“ id_accessoire”不能为空（空）。

当我通过Advanced Rest Client发送JSON时，字段id_accessoire不为空。

首先，这是我的实体（文件Affaire.java），所有字段都在我的数据库中：

@Entity
@Data
@Table(name = "affaire")
@JsonIdentityInfo(generator=ObjectIdGenerators.PropertyGenerator.class, property="id")
public class Affaire implements Serializable {
  private static final long serialVersionUID = 1L;

  @Id
  @GeneratedValue(strategy = GenerationType.IDENTITY)
  @Column(name = "id", insertable = false, nullable = false)
  private Integer id;

  @Column(name = "sn", nullable = false)
  private String sn;

  @Column(name = "zc")
  private String zc;

  @Column(name = "certificat")
  private String certificat;

  @Column(name = "etat", nullable = false)
  private Boolean etat;

  @Column(name = "finEval", nullable = false)
  private Date finEval;

  @Column(name = "finRep", nullable = false)
  private Date finRep;

  @Column(name = "limiteCalendaire", nullable = false)
  private String limiteCalendaire;

  @Column(name = "date_lancement", nullable = false)
  private Date dateLancement;

  @Column(name = "accordClient", nullable = false)
  private boolean accordClient;

  @Column(name="idAccessoire", insertable = false, updatable = false)
  private Integer idAccessoire;

  @Column(name="idFlux", insertable = false, nullable = false, updatable = false)
  private Integer idFlux;

  @Column(name="idReparation", insertable = false, nullable = false, updatable = false)
  private Integer idReparation;

  @Column(name="idVariante", insertable = false, nullable = false, updatable = false)
  private Integer idVariante;

  @ManyToOne(fetch = FetchType.LAZY)
  @JoinColumn(name="idAccessoire", nullable = false)
  @JsonBackReference(value = "affaireAccess")
  private Accessoire accessoire;

  @ManyToOne(fetch = FetchType.LAZY)
  @JoinColumn(name="idFlux", nullable = false)
  @JsonBackReference(value = "affaireFlux")
  private Flux flux;

  @ManyToOne(fetch = FetchType.LAZY)
  @JoinColumn(name="idReparation", nullable = false)
  @JsonBackReference(value = "affaireRep")
  private Reparation reparation;

  @ManyToOne(fetch = FetchType.LAZY)
  @JoinColumn(name="idVariante", nullable = false)
  @JsonBackReference(value = "affaireVariante")
  private Variante variante;

  @OneToMany(mappedBy = "affaire", cascade=CascadeType.ALL, fetch=FetchType.LAZY)
  //@JsonManagedReference(value = "affecterAffaire")
  @ToString.Exclude
  private List<Affecter> affecters;

}

最后，这是我尝试发布的JSON，但不起作用：

{
  "sn":"4444AAA",
  "zc":null,
  "certificat":null,
  "etat" : false,
  "finEval": "2019-08-25",
  "finRep": "2019-09-14",
  "limiteCalendaire":"10R28",
  "dateLancement":"2019-07-19",
  "accordClient" : false,
  "idAccessoire" : 1,
  "idFlux": 1,
  "idReparation": 2,
  "idVariante" : 7,
}

错误是字段“ id_accessoire_不能为空（空）

Answer 1

从您的实体类中，我可以看到idAccessoire列中的不可插入内容不可更新。

 @Column(name="idAccessoire", insertable = false, updatable = false)
  private Integer idAccessoire;

这意味着无论您在代码中设置哪个值，该值都将被忽略。

现在，如果在表配置中将idAccessoire定义为不可为空的字段，则会引发此错误。

1）您是否真的希望此字段不可插入或不可更新？
2）如果必须在数据库中将此列指定为非null，请尝试指定默认值（如果它适合您的业务逻辑）。

无法执行语句；嵌套的异常是org.hibernate.exception.ConstraintViolationException：无法执行语句

1 个答案: