根据单词相似度将一个varchar与另一个varchar进行比较

时间:2019-07-20 01:44:39

标签: php mysql sql

我有两个varchar,我试图根据varchar中单词的相似性进行比较和显示。例如,如果我有字符串:“ hello mellow guy”,并将其与包含以下内容的表进行比较:

“你好海洋人”
“再见电脑用品”
“你好仙人掌仙人掌”

然后它将基于它们共有多少个单词来显示结果,例如:

“你好仙人掌”
“你好海洋人”
“再见的电脑东西”

预先感谢

1 个答案:

答案 0 :(得分:0)

通常,可以通过标记原始语句和其他每个语句来做到这一点,对两个结果数组之间的交点进行计数并相应地排序,这是示例代码:

<?php

$myPhrase = "hello mellow fellow";
$otherPhrases = ["hello ocean man", "goodbye computer thing", "hello fellow cactus"];
$resultsOrdered = [];


$myWords = explode(" ", $myPhrase);
foreach($otherPhrases as $otherPhrase) {
    $otherWords = explode(" ", $otherPhrase);
    $intersectWords = array_intersect($myWords, $otherWords);
    $resultsOrdered[$otherPhrase] = count($intersectWords);
}

arsort($resultsOrdered);

foreach($resultsOrdered as $phrase => $wordCountInCommon) {
    echo $phrase." (".$wordCountInCommon. " words in common)".PHP_EOL;
}
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