Question

Button onPress不起作用，根本没有调用onButtonPress（）方法。我不确定自己在做什么错。

我有未打印的console.log语句。顺便说一下，下面的代码来自Stephen Grider的本机udemy cource

下面是loginForm.js的代码

任何帮助将不胜感激。

import React, { Component } from 'react';
import { Text } from 'react-native';
import firebase from 'firebase';
import { Button, Card, CardSection, Input, Spinner, Field } from './common';

class LoginForm extends Component {
  state = { email: '', password: '', error: '', loading: false };

  onButtonPress() {
    const { email, password } = this.state;
    console.log('da');
    this.setState({ error: '', loading: true });

    firebase
      .auth()
      .signInWithEmailAndPassword(email, password)
      .then(this.onLoginSuccess.bind(this))
      .catch(() => {
        firebase
          .auth()
          .createUserWithEmailAndPassword(email, password)
          .then(this.onLoginSuccess.bind(this))
          .catch(this.onLoginFail.bind(this));
      });
  }

  onLoginFail() {
    this.setState({
      error: 'Authentication Failed',
      loading: false
    });
  }

  onLoginSuccess() {
    this.setState({
      email: '',
      password: '',
      loading: false,
      error: ''
    });
  }

  renderButton() {
    if (this.state.loading) {
      return <Spinner size="small" />;
    }

    return <Button onPress={this.onButtonPress.bind(this)}>Log in</Button>;
  }

  render() {
    return (
      <Card>
        <CardSection>
          <Field
            placeholder="user@gmail.com"
            label="Email"
            value={this.state.email}
            onChangeText={email => this.setState({ email })}
          />
        </CardSection>
        <CardSection>
          <Field
            secureTextEntry
            placeholder="password"
            label="Password"
            value={this.state.password}
            onChangeText={password => this.setState({ password })}
          />
        </CardSection>

        <Text style={styles.errorTextStyle}>{this.state.error}</Text>

        <CardSection>{this.renderButton()}</CardSection>
      </Card>
    );
  }
}

const styles = {
  errorTextStyle: {
    fontSize: 20,
    alignSelf: 'center',
    color: 'red'
  }
};

export default LoginForm;

Answer 1

您需要将this绑定到renderButton，可以使用自动绑定this的箭头功能，

renderButton = () => { //Arrow function binds this automatically
  if (this.state.loading) {
    return <Spinner size="small" />;
  }

  return <Button onPress={this.onButtonPress.bind(this)}>Log in</Button>;
}

React Native Button onPress不起作用

1 个答案: