为什么不填充Formik的“ touched”属性?

时间:2019-08-07 01:42:41

标签: reactjs react-bootstrap formik

我正在使用React,Formik,react-bootstrap和yup进行表单验证。我正在尝试显示验证错误,但是touched属性未填充字段。

const schema = yup.object({
  name: yup.string().required(),
  email: yup
    .string()
    .email()
    .required(),
});

const ChildForm = props => {
  const { child: { name = '', email = '' } = {} } = props;
  const submitHandler = ({name, email}) => console.log(name, email);

  return (
    <Formik
      validationSchema={schema}
      onSubmit={submitHandler}
      initialValues={{ name, email }}
      render={({ handleSubmit, handleChange, values, touched, errors }) => 
      {
        console.log('touched: ', touched);
        return (
          <Form noValidate className="mt-4" onSubmit={handleSubmit}>
            <Form.Row>
              <Form.Group as={Col} controlId="name">
                <Form.Label>Full Name</Form.Label>
                <Form.Control
                  name="name"
                  required
                  value={values.name}
                  onChange={handleChange}
                  isValid={touched.name && !errors.name}
                  isInvalid={touched.name && errors.name}
                  type="text"
                  placeholder="Your child's name"
                />
                <Form.Control.Feedback>Looks good!</Form.Control.Feedback>
                <Form.Control.Feedback type="invalid">
                  {errors.name || 'Please enter your child\'s name'}
                </Form.Control.Feedback>
              </Form.Group>
            </Form.Row>
            <Form.Row>
              <Form.Group as={Col} controlId="email">
                <Form.Label>Email Address</Form.Label>
                <Form.Control
                  name="email"
                  required
                  value={values.email}
                  onChange={handleChange}
                  isValid={touched.email && !errors.email}
                  isInvalid={touched.email && errors.email}
                  type="text"
                  placeholder="Your child's email address"
                />
                <Form.Control.Feedback>
                  No spam, we promise!
                </Form.Control.Feedback>
                <Form.Control.Feedback type="invalid">
                  {errors.email || 'Please enter a valid email address'}
                </Form.Control.Feedback>
              </Form.Group>
            </Form.Row>
            <Form.Row className="float-right">
              <Button variant="success" onClick={handleSubmit}>
                <Icon icon={faSave} />
                &nbsp; Submit
              </Button>
            </Form.Row>
          </Form>
        );
      }}
    />
  );
}

我在这里做错了什么? console.log(touched)始终显示一个空对象。

2 个答案:

答案 0 :(得分:0)

通过访问在handleBlur函数参数中传递的render函数,并将其作为每个表单元素的onBlur处理程序,使它起作用。不知道是否需要这样做,因为我正在使用react-bootstrap表单组件,但是react-bootstrap文档有一个Formik示例,但是touched对象没有得到更新。

(
    <Formik
      validationSchema={schema}
      onSubmit={submitForm}
      initialValues={{ name, email }}
      render={({
        handleSubmit,
        handleChange,
        handleBlur, // handler for onBlur event of form elements
        values,
        touched,
        errors,
      }) => {
        return (
          <Form noValidate className="mt-4" onSubmit={handleSubmit}>
            <Form.Row>
              <Form.Group as={Col} controlId="nameControl">
                <Form.Label>Full Name</Form.Label>
                <Form.Control
                  name="name"
                  required
                  value={values.name}
                  onChange={handleChange}
                  onBlur={handleBlur} // This apparently updates `touched`?
                  isValid={touched.name && !errors.name}
                  isInvalid={touched.name && errors.name}
                  type="text"
                  placeholder="Your child's name"
                />
                <Form.Control.Feedback>Looks good!</Form.Control.Feedback>
                <Form.Control.Feedback type="invalid">
                  {errors.name || 'Please enter your child\'s name'}
                </Form.Control.Feedback>
              </Form.Group>
            </Form.Row>

答案 1 :(得分:0)

@djheru您的解决方案是正确的,因为Formik在touched事件上而不是在blur上设置change标志。 Here是Formik作者对此的评论: 您必须调用Formiks handleBlur来通知Formik已触发blur事件-是的,需要这些处理程序。