选择总和（amt）大于值的所有行

Question

我有一个以Invoice和amt为列的下表

+----------+------+
| Invoice  |  Amt | Ledger
+----------+------+
|        1 |    5 |  101
|        1 |    7 |  102
|        1 |   10 |  103
|        1 |    6 |  104
+----------+------+

我需要一直排除行，直到sum（amt）<= value并获取所有下一行。

假设值为12

则输出行应为

+----------+------+
| Invoice  |  Amt |Ledger
+----------+------+
|        1 |   10 |103
|        1 |    6 |104
+----------+------+

假设值是11

则输出行应为

+----------+------+
| Invoice  |  Amt |Ledger
+----------+------+
|        1 |    7 |102
|        1 |   10 |103
|        1 |    6 |104
+----------+------+

任何帮助/建议将不胜感激。

Answer 1

SQL表表示无序集（技术上是多集，因为允许重复），所以我假设您有一个排序列。您所关心的是累计金额。剩下的只是过滤：

select t.*
from (select t.*,
             sum(amt) over (partition by invoice order by <ordering col>) as cumulative_amt
      from t
     ) t
where cumulative_amt >= 12;