Question

我尝试比较不同类型的火腿肠。但是我不明白，如何为以下问题构建自己的<button class="switcher switcher__Last collapsible">X1</button> <div class="collapsibleContent"> <span class="choise__block-item">Text</span> <span class="choise__block-item">Text</span> <span class="choise__block-item">Text</span> </div> <button class="switcher switcher__Last collapsible">X2</button> <div class="collapsibleContent"> <span class="choise__block-item">Text</span> <span class="choise__block-item">Text</span> <span class="choise__block-item">Text</span> </div>：

Matcher

String[] exp = new String[]{"x", "y", "z"}; DAO[] cur = getFromExternalWebservice(); Assert.assertThat("wrong strings", exp, Matchers.arrayContainingInAnyOrder(cur));是以下类的数组：

cur

上面的测试实际上应该比较class DAO { public String id; public String name; }中的Strings和数组exp中name个对象的DAO属性。我无法在cur上进行任何更改（例如添加DAO方法）。

我可以将Web服务的结果转换为toString()数组，将其发送给Matcher，如下所示：

names

但这很丑陋，我如何构建一个String names[] = new String[cur.length]; for (int i = 0; i < cur.length; i++) { names[i] = cur[i].name; } Assert.assertThat("wrong strings", exp, Matchers.arrayContainingInAnyOrder(names));来比较Matcher而没有任何数据副本？

Answer 1

我实现了第一个想法：

public class IsIn extends BaseMatcher<String> {

   class DAOIterator implements Iterable<String>, Iterator<String> {
        private final DAO[] collection;
        private int idx;

        public DAOIterator(DAO[] elements) {
            this.collection = elements;
            idx = 0;
        }

        @Override
        public boolean hasNext() {
            return (this.collection.length > this.idx);
        }

        @Override
        public String next() {
            return this.collection[this.idx++].name;
        }

        @Override
        public Iterator<String> iterator() {
            return new DAOIterator(this.collection);
        }
    }

    private final DAO[] collection;

    public IsIn(DAO[] elements) {
        this.collection = elements;
    }

    @Override
    public boolean matches(Object o) {
        for (DAO d : this.collection) {
            if (o == null ? d.name == null : o.equals(d.name)) {
                return true;
            }
        }
        return false;
    }

    @Override
    public void describeTo(Description buffer) {
        buffer.appendText("one of ");
        buffer.appendValueList("{", ", ", "}", new DAOIterator(this.collection));
    }

}

在JUnit测试用例上调用它：

String[] exp = new String[]{"x", "y", "z"};
DAO[] cur = getFromExternalWebservice();
Assert.assertThat("wrong strings", Arrays.asList(exp), Matchers.everyItem(new IsIn(cur)));

如何使用Hamcrest比较不同类型

1 个答案: