为什么C#没有词法嵌套函数?

时间:2009-02-23 02:39:41

标签: c# scheme

为什么C#语言设计师可能没有包含对此类内容的支持(移植自Structure and Interpretation of Computer Programs,第二版,第30页):

/// <summary>Return the square root of x.</summary>
double sqrt(double x) {
  bool goodEnough(double guess) {
    return Math.Abs(square(guess) - x) < 0.001;
  }
  double improve(double guess) {
    return average(guess, x / guess);
  }
  double sqrtIter(double guess) {
    return goodEnough(guess) ? guess : sqrtIter(improve(guess));
  }
  sqrtIter(1.0);
}

2 个答案:

答案 0 :(得分:36)

事实上,C#就是这样。

double sqrt(double x) {
    var goodEnough = new Func<double, bool>(guess =>
        Math.Abs(square(guess) - x) < 0.001
    );
    var improve = new Func<double, double>(guess =>
        average(guess, x / guess)
    );
    var sqrtIter = default(Func<double, double>);
    sqrtIter = new Func<double, double>(guess =>
        goodEnough(guess) ? guess : sqrtIter(improve(guess))
    );
    return sqrtIter(1.0);
}

答案 1 :(得分:8)

正如Justice所说,你可以用C#3.5和lambdas来做;如果你有C#2.0,你可以使用匿名函数,虽然它不那么性感:

double sqrt(double x) {
    Func<double, bool> goodEnough = delegate(double guess) {
        return Math.Abs(square(guess) - x) < 0.001;
    };
    Func<double, double> improve = delegate(double guess) {
        return average(guess, x / guess);
    };
    Func<double, double> sqrtIter = null;
    sqrtIter = delegate(double guess) {
        return goodEnough(guess) ? guess : sqrtIter(improve(guess));
    };
    return sqrtIter(1.0);
}

编辑:我忘了,Func没有在C#2.0中定义,所以你必须自己定义:

 public delegate TResult Func<T, TResult>(T guess);