Question

我有一张桌子，里面有州，地区，区，建筑和类的树。每行都有一个节点ID和一个父ID。我使用以下

select name, child node, parent id from tableA  
connect by prior child node = parent id

我得到：

CA  
  CENTRAL REGION  
    FRESNO DISTRICT  
     ST Jim BUILDING  
     ST joe BUILDING  
     st tom BUILDING  
     st sue BUILDING  
       JIMS CLASS  
       JOES CLASS  
       TOM CLASS  
       SUE CLASS

问题是，在建筑层面，所有建筑物都是一个接一个地列出，然后是所有类别。但是我想列出建筑物和类，它是下一个建筑物的父母，如下所示

 FRESNO DISTRICT  
    st jim building  
      jims class  
    st joes building  
      joes class...

节点ID和父ID是正确的，只是列出了父节点的所有子节点，然后是该子节点的所有子节点。它没有显示哪个孩子和父母一起去。

我想从上到下显示树，例如CA，中部地区，弗雷斯诺区，St Joe Building，Mary女士班，女士

Answer 1

除非您使用不带SIBLINGS关键字的ORDER BY，否则应保留层次结构排序。

select name, id, parent_id
from tableA
connect by prior id = parent_id
start with parent_id is null
order siblings by name;

使用此数据：

create table tableA(id number, name varchar2(100), parent_id number);

insert into tableA
select 1 id, 'CA' name, null parent_id from dual union all
select 2, 'CENTRAL REGION', 1 from dual union all
select 3, 'FRESNO DISTRICT', 2 from dual union all
select 4, 'ST Jim BUILDING', 3 from dual union all
select 5, 'ST joe BUILDING', 3 from dual union all
select 6, 'st tom BUILDING', 3 from dual union all
select 7, 'st sue BUILDING', 3 from dual union all
select 8, 'JIMS CLASS', 4 from dual union all
select 9, 'JOES CLASS', 5 from dual union all
select 10, 'TOM CLASS', 6 from dual union all
select 11, 'SUE CLASS', 7 from dual;

需要在Oracle Hierarchical查询中在父级下的子级下显示孙子

1 个答案: