Question

美好的一天！有一张桌子：

CREATE TABLE table
(
start_range  varcahar2(10),
end_range varcahar2(10),
val_range NUMBER(10)
);

在初始阶段，我们填写了两个字段：start_range和end_range。

start_range = a1;
end_range = a5;

您可以在Apex的a1-a5 (a1, a2, a3, a4, a5)范围内填写一个完全不同的表吗？

Answer 1

看起来像一个层次查询。

测试用例：

SQL> CREATE TABLE test
  2  (
  3     start_range  VARCHAR2 (10),
  4     end_range    VARCHAR2 (10),
  5     val_range    NUMBER (10)
  6  );

Table created.

SQL> INSERT INTO test
  2       VALUES ('a1', 'a5', NULL);

1 row created.

SQL> INSERT INTO TEST
  2       VALUES ('L4819201', 'L4819205', NULL);

1 row created.

SQL> SELECT * FROM test;

START_RANG END_RANGE   VAL_RANGE
---------- ---------- ----------
a1         a5
L4819201   L4819205

查询：

SQL> INSERT INTO test2 (val)
  2     SELECT    SUBSTR (start_range, 1, 1)
  3            || TO_CHAR (
  4                  (  TO_NUMBER (REGEXP_SUBSTR (start_range, '\d+$'))
  5                   + COLUMN_VALUE
  6                   - 1))
  7               AS val
  8       FROM test
  9            CROSS JOIN
 10            TABLE (
 11               CAST (
 12                  MULTISET (
 13                         SELECT LEVEL
 14                           FROM DUAL
 15                     CONNECT BY LEVEL <=
 16                                     TO_NUMBER (
 17                                        REGEXP_SUBSTR (end_range, '\d+$'))
 18                                   - TO_NUMBER (
 19                                        REGEXP_SUBSTR (start_range, '\d+$'))
 20                                   + 1) AS SYS.odcinumberlist))
 21      WHERE start_range = '&start_range';
Enter value for start_range: a1

5 rows created.

SQL> /
Enter value for start_range: L4819201

5 rows created.

结果：

SQL> SELECT * FROM test2 ORDER BY val;

VAL
----------
a1
a2
a3
a4
a5
L4819201
L4819202
L4819203
L4819204
L4819205

10 rows selected.

SQL>

Answer 2

您可以使用以下内容：

SELECT
    DISTINCT PREFIX || ( START_RANGE + LEVEL - 1 )
FROM
    (
        SELECT
            REGEXP_SUBSTR(START_RANGE, '^[[:alpha:]]+') AS PREFIX,
            REGEXP_SUBSTR(START_RANGE, '\d+$') AS START_RANGE,
            REGEXP_SUBSTR(END_RANGE, '\d+$') AS END_RANGE
        FROM
            TEST
    )
CONNECT BY
    LEVEL <= END_RANGE - START_RANGE + 1
ORDER BY 1;

我假设您的开始和结束范围的前缀具有格式（string || number）

db<>fiddle demo

干杯！

范围填充表

2 个答案: