将zmq :: proxy与REQ / REP模式一起使用

时间:2019-09-10 12:29:45

标签: c++ c++11 zeromq

我试图了解zmq :: proxy的工作原理,但遇到问题:我想将消息路由到正确的工作人员,但似乎忽略了身份和信封:示例我想将消息从client1路由到worker2,并将消息从client2路由到worker1,但是似乎这些消息是基于基于“第一个可用工作程序”的规则提供的。 我是在做错什么,还是我误解了身份的运作方式?

#include <atomic>
#include <cassert>
#include <chrono>
#include <iostream>
#include <thread>
#include <mutex>

#include <zmq.hpp>
#include <zmq_addon.hpp>

using namespace zmq;
std::atomic_bool running;
context_t context(4);
std::mutex mtx;

void client_func(std::string name, std::string target, std::string message)
{
    std::this_thread::sleep_for(std::chrono::seconds(1));

    socket_t request_socket(context, socket_type::req);
    request_socket.connect("inproc://router");
    request_socket.setsockopt( ZMQ_IDENTITY, name.c_str(), name.size());

    while(running)
    {   
        multipart_t msg;
        msg.addstr(target);
        msg.addstr("");
        msg.addstr(message);

        std::cout << name << "sent a message: " << message << std::endl;
        msg.send(request_socket);
        multipart_t reply;
        if(reply.recv(request_socket))
        {
            std::unique_lock<std::mutex>(mtx);
            std::cout << name << " received a reply!" << std::endl;

            for(size_t i = 0 ; i < reply.size() ; i++)
            {
                std::string theData(static_cast<char*>(reply[i].data()),reply[i].size());
                std::cout << "Part " << i << ": " << theData << std::endl;
            }

        }

        std::this_thread::sleep_for(std::chrono::seconds(1));
    }

    request_socket.close();
}


void worker_func(std::string name, std::string answer)
{
    std::this_thread::sleep_for(std::chrono::seconds(1));

    socket_t response_socket(context, socket_type::rep);
    response_socket.connect("inproc://dealer");
    response_socket.setsockopt( ZMQ_IDENTITY, "resp", 4);

    while(running)
    {
        multipart_t request;

        if(request.recv(response_socket))
        {
            std::unique_lock<std::mutex>(mtx);

            std::cout << name << " received a request:" << std::endl;
            for(size_t i = 0 ; i < request.size() ; i++)
            {
                std::string theData(static_cast<char*>(request[i].data()),request[i].size());
                std::cout << "Part " << i << ": " << theData << std::endl;
            }

            std::string questioner(static_cast<char*>(request[0].data()),request[0].size());

            multipart_t msg;
            msg.addstr(questioner);
            msg.addstr("");
            msg.addstr(answer);

            msg.send(response_socket);
        }
    }

    response_socket.close();
}


int main(int argc, char* argv[])
{
    running = true;

    zmq::socket_t dealer(context, zmq::socket_type::dealer);
    zmq::socket_t router(context, zmq::socket_type::router);
    dealer.bind("inproc://dealer");
    router.bind("inproc://router");

    std::thread client1(client_func, "Client1", "Worker2", "Ciao");
    std::thread client2(client_func, "Client2", "Worker1", "Hello");
    std::thread worker1(worker_func, "Worker1","World");
    std::thread worker2(worker_func, "Worker2","Mondo");

    zmq::proxy(dealer,router);

    dealer.close();
    router.close();

    if(client1.joinable())
        client1.join();

    if(client2.joinable())
        client2.join();

    if(worker1.joinable())
        worker1.join();

    if(worker2.joinable())
        worker2.join();

    return 0;
}

1 个答案:

答案 0 :(得分:1)

来自docs

  

当前端是ZMQ_ROUTER套接字,后端是ZMQ_DEALER套接字时,代理应充当共享队列,该队列从一组客户端收集请求,并在一组服务之间公平地分配这些请求。请求应从前端连接中公平排队,并在后端连接中平均分配。答复应自动返回到提出原始请求的客户。

代理处理多个客户端,并使用多个工作进程来处理请求。该身份用于将响应发送到正确的客户端。您不能使用标识来“选择”特定工作人员。

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