如何遍历数组并将每个项目分配给每个字典键

Question

我有一个数组和一个字典

var list = ["A", "B", "C","D"]

var dict = [
    "Chapter 1 Body" : "",
    "Chapter 2 Body" : "",
    "Chapter 3 Body" : "",
    "Chapter 4 Body" : ""
]

我想遍历列表数组并将每个项目分配给字典的每个键。这是我打印字典时的预期输出：

["Chapter 1 Body": "A", "Chapter 2 Body": "B", "Chapter 3 Body": "C", "Chapter 4 Body": "D"]

注意：订单应与打印输出相同。

Answer 1

您可以使用zip并对键进行排序（如果字母排序顺序是字典键的正确顺序）

dict = zip(dict.keys.sorted(), list).reduce(into: [:]) {$0[$1.0] = $1.1} 

如果键以其他顺序排序，则需要将它们按正确的顺序放在数组中，但解决方案基本相同

var chapters = ["Chapter 1 Body", "Chapter 2 Body", "Chapter 3 Body", "Chapter 4 Body"]
let dict = zip(chapters, list).reduce(into: [:]) {$0[$1.0] = $1.1} 

Answer 2

var i = 0
for k in dict.keys.sorted() {
    dict[k] = list[i]
    i += 1
}