Android检查移动数据和WiFi连接

时间:2019-10-06 17:42:40

标签: android kotlin

我只想实现一个查询,每次单击按钮时都会检查启用了哪些WiFi / Mobile设置。我的代码得到了奇怪的结果。

如何实现正确的行为,以便知道哪些适配器已打开,哪些适配器未打开?

private fun check() {
    val connectivityManager = getSystemService(Context.CONNECTIVITY_SERVICE) as ConnectivityManager

    connectivityManager.run {
        connectivityManager.getNetworkCapabilities(connectivityManager.activeNetwork)?.run {
            if (hasTransport(NetworkCapabilities.TRANSPORT_WIFI)) {
                Log.d("TAG", "WIFI YES")
            } else {
                Log.d("TAG", "WIFI NO")
            }

            if (hasTransport(NetworkCapabilities.TRANSPORT_CELLULAR)) {
                Log.d("TAG", "MOBILE YES")
            } else {
                Log.d("TAG", "MOBILE NO")
            }
        }
    }
}
WiFi   Mobile     --output-->     WiFi     Mobile
 ×       ×                         no output
 ✓       ×                         yes       no
 ×       ✓                         no        no
 ✓       ✓                         yes       no

1 个答案:

答案 0 :(得分:0)

根据您的要求尝试以下代码行检查连接是否可用

public static boolean isNetworkConnected() {

    ConnectivityManager connectivityManager = (ConnectivityManager)TaxiappApplication.getInstance().getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo wifi = connectivityManager.getNetworkInfo(ConnectivityManager.TYPE_WIFI);
    NetworkInfo mobile = connectivityManager.getNetworkInfo(ConnectivityManager.TYPE_MOBILE);
    NetworkInfo bluetooth = connectivityManager.getNetworkInfo(ConnectivityManager.TYPE_BLUETOOTH);
    NetworkInfo wimax = connectivityManager.getNetworkInfo(ConnectivityManager.TYPE_WIMAX);

    if (wifi == null && mobile == null && bluetooth == null && wimax == null) {
        return false;
    }

    if (wifi != null && wifi.isConnected()) {
        return true;
    }

    if (mobile != null && mobile.isConnected()) {
        return true;
    }

    if (bluetooth != null && bluetooth.isConnected()) {
        return true;
    }

    if (wimax != null && wimax.isConnected()) {
        return true;
    }

    return false;
}

希望对您有帮助

相关问题