Question

我使用Mockito在Flutter上编写测试。我有一个模拟的类和方法，它们的参数均为函数-Function（），此方法返回StreamSubscription。我需要将这些参数传递给listen()函数的调用，但找不到解决方法。（请参见示例）有人可以帮我吗？

我尝试像示例中一样使用argThat(anyNamed('nameOfArgument')传递它们，但是测试引发错误-在方法存根之外（通过when使用“ anyNamed”参数匹配器）

class MockPhotoLibraryService extends Mock implements PhotoLibraryService {}

PhotoLibraryService setupMockPhotoLibraryService() {
  final photoLibraryService = MockPhotoLibraryService();

  when(
    photoLibraryService.getPhotosForPeriod(
        onData: anyNamed('onData'),
        onDone: anyNamed('onDone'),
        onError: anyNamed('onError')),
  ).thenAnswer((_) => Stream<Photo>.fromFuture(
          Future<Photo>.delayed(Duration(milliseconds: 50), () => Photo()))
      .listen(argThat(anyNamed('onData')), //need to pass argument named onData
          onDone: argThat(anyNamed('onDone')), //need to pass argument named onDone
          onError: argThat(anyNamed('onError')), //need to pass argument named onError
          cancelOnError: true));

  return photoLibraryService;
}

我需要这些参数函数由Future调用，以使我的可测试小部件正常工作。

Answer 1

您可以通过Invocation对象访问原始调用参数。它作为参数传递给thenAnswer回调函数。

when(photoLibraryService.getPhotosForPeriod(
  onData: anyNamed('onData'),
  onDone: anyNamed('onDone'),
  onError: anyNamed('onError'),
)).thenAnswer((Invocation invocation) {
  final namedArgs = invocation.namedArguments;
  final onData = namedArgs[Symbol('onData')] as Function(Photo);
  final onDone = namedArgs[Symbol('onDone')] as Function();
  final onError = namedArgs[Symbol('onError')] as Function(dynamic);

  return Stream<Photo>.fromFuture(
    Future<Photo>.delayed(Duration(milliseconds: 50), () => Photo()),
  ).listen(onData, onDone: onDone, onError: onError, cancelOnError: true);
});

Dart和Mockito。如何在模拟方法中调用Function（）参数

1 个答案: