抛出异常

Question

如果用户输入失败，我尝试抛出异常TooLongEx失败。永远坚持下去:(

import java.util.Scanner;
public class MessageTooLong extends Exception {
    public static void main(String args[])
    throws TooLongEx {
        Scanner keyboard = new Scanner(System.in);
        String line;
        char preference;
        int length;
        boolean go = true;
        while (go) {
            System.out.println("Enter a line of text.");
            System.out.println("Use no more than 20 characters.");
            line = keyboard.next();
            length = line.length();
            if (length <= 20) {
                    System.out.println("You entered " + length + " characters, which is an acceptable length.");
                    System.out.println("Would you like to enter another line?");
                    System.out.println("Enter 'y' to continue or 'n' to quit.");
                    preference = keyboard.next().charAt(0);
                if ((preference == 'y') || (preference == 'Y')) {
                    go = true;
                } else {
                    go = false;
                }
            } else {
                throw new TooLongEx();
            }
        }
    }
}

Answer 1

似乎对我来说很好。

有关

class TooLongEx extends Exception {}

我得到（输入长度​​> 20）

  

线程“main”TooLongEx中的异常     在   MessageTooLong.main（MessageTooLong.java:26）