Question

我编写了以下代码来解决代码战中的问题：

char *series_sum(unsigned long int n){
    double sum=0;
    static char a[10];
    for(int i=1;i<=n;i++){sum=sum+1.0/(3*i-2);}
    sprintf(a,"%.2lf",sum);
    return a;
}

问题很简单，它只希望您打印序列的第n个部分和，并将其作为带2个小数点的字符串（“ a.bc”）返回。但是我得到了错误：

munmap_chunk（）：无效的指针：0x00000000006031b1

编辑：这是测试功能的代码。

#include <criterion/criterion.h>
#include <stddef.h>

char *series_sum(const size_t n);

Test(ExampleTests, ShouldPassAllTheTestsProvided) {
 {
   const char *expected = "1.00";
   char *received = series_sum(1);
   cr_assert_str_eq(expected, received, "Expected: %s Received: %s", expected, received);
   free(received); received = NULL;
 }

 {
   const char *expected = "1.25";
   char *received = series_sum(2);
   cr_assert_str_eq(expected, received, "Expected: %s Received: %s", expected, received);
   free(received); received = NULL;
 }

 {
   const char *expected = "1.39";
   char *received = series_sum(3);
   cr_assert_str_eq(expected, received, "Expected: %s Received: %s", expected, received);
   free(received); received = NULL;
 }
}

Answer 1

由于尚无关于您其他代码的信息，让我推测一下：调用代码的功能类似于：

field1

该免费电话尝试释放静态内容。您可以从malloc获得的指针上调用free。您不应该尝试在静态缓冲区上调用它。

如何修复C中的“ munmap_chunk（）：无效指针”错误？

1 个答案: