Question

是否有快速方法在MS Access中复制Count（Distinct [f]）的效果？

例如：

单个推荐的数据表（实际数据中有几千个）：

| Referral ID | Assessment Date | Assessment Team | Service Provided | Service Team
| 1           | 02/01/2008      | AAA             | BBB              | AAA
| 1           | 02/01/2008      | AAA             | CCC              | AAA
| 1           | 02/01/2008      | AAA             | DDD              | BBB
| 1           | 03/01/2008      | BBB             | EEE              | CCC

我想要一个查询：

| Referral ID | Number of Assessments | Teams Assessing | Services Provided | No Teams Providing
| 1           | 2                     | 2               | 4                 | 3

任何帮助表示赞赏！

Answer 1

这有点复杂，但可能适合。 Imp是你的桌子。

SELECT DISTINCT a.[Referral ID], b.CountOfADate, c.CountOfATeam, d.CountOfService, e.CountOfSTeam

FROM (((imp AS a 

INNER JOIN 
    (SELECT b1.[Referral ID], Count(b1.ADate) AS CountOfADate
     FROM (SELECT DISTINCT t.[Referral ID], t.[Assessment Date] As ADate FROM imp As t) AS b1
     GROUP BY b1.[Referral ID]) AS b 
ON a.[Referral ID] = b.[Referral ID]) 

INNER JOIN 
    (SELECT c1.[Referral ID], Count(c1.ATeam) AS CountOfATeam
    FROM (SELECT DISTINCT t.[Referral ID], t.[Assessment Team] As ATeam FROM imp As t) AS c1
    GROUP BY c1.[Referral ID]) AS c 
ON a.[Referral ID] = c.[Referral ID]) 

INNER JOIN 
    (SELECT d1.[Referral ID], Count(d1.Service) AS CountOfService
    FROM (SELECT DISTINCT t.[Referral ID], t.[Service Provided] As Service FROM imp As t) AS d1
    GROUP BY d1.[Referral ID]) AS d 
ON a.[Referral ID] = d.[Referral ID]) 

INNER JOIN 
    (SELECT e1.[Referral ID], Count(e1.STeam) AS CountOfSTeam
    FROM (SELECT DISTINCT t.[Referral ID], t.[Service Team] As STeam FROM imp As t) AS e1
    GROUP BY e1.[Referral ID]) AS e 
ON a.[Referral ID] = e.[Referral ID];

MS Access中重复计数（Distinct [f]）

1 个答案: