Question

for (int i = 0; i < client.Folders.Count; i++)
        {

            (ContextMenuListView.Items[1] as ToolStripMenuItem).DropDownItems.Add(client.Folders[i].Name);//add Folder to Move To
            (ContextMenuListView.Items[2] as ToolStripMenuItem).DropDownItems.Add(client.Folders[i].Name);                
        }

如何在Items [1]或Items [2]中获取子项目？

Answer 1

ToolStripItemCollection.Add(string)（DropDownItems.Add（））将返回新的ToolStripItem ...

另一方面，ToolStripItemCollection DropDownItems

引用了所有其他子项

因此，获取两个创建项目的简便方法是：

(ContextMenuListView.Items[1] as ToolStripMenuItem).DropDownItems.Add(client.Folders[i].Name);
(ContextMenuListView.Items[2] as ToolStripMenuItem).DropDownItems.Add(client.Folders[i].Name);

会变成：

ToolStripItem firstItem = (ContextMenuListView.Items[1] as ToolStripMenuItem).DropDownItems.Add(client.Folders[i].Name);
ToolStripItem secondItem = (ContextMenuListView.Items[2] as ToolStripMenuItem).DropDownItems.Add(client.Folders[i].Name);

或访问所有子项：

foreach(ToolStripItem i in (ContextMenuListView.Items[1] as ToolStripMenuItem).DropDownItems.OfType<ToolStripItem>())
{
   //...
}

或访问特定子项：

var specificItem = (ContextMenuListView.Items[1] as ToolStripMenuItem).DropDownItems.Item[0];

如何在contextmenustrip上添加subitem上的事件？ C＃

1 个答案: