Question

我的关注基于我先前询问并得到解决的same question。

起初我以为我得到了正确的答复，但是看到我没有。我的数据是这样的：

如果我这样过滤

var result = overdues.Where(a=>a.Accounts.Any(b=>b.AccountId.Equals("JKB2")));

我得到这样的结果：

但是我希望结果仅包含等于JKB2的帐户，而不包含等于JKB2的帐户。因此，我在这里强调的应该是结果，而不是其他：

从技术上讲，结果应该是这样的（我只是以JSON的形式编写了一个伪代码）：

    [
    {
    Slab: T3,
    Value: 500,
    Percentage: 0
    Accounts: {
    AccountId:JKB2,
    AccountName:JKB2,
    SalesCode:JKB,
    Value:500
    }
    },
{
    Slab: T5,
    Value: 500,
    Percentage: 0
    Accounts: {
    AccountId:JKB2,
    AccountName:JKB2,
    SalesCode:JKB,
    Value:500
    }
    }
    ]

我的LinqPad工作在这里：

public class OverdueModel
    {
        public string Slab { get; set; }
        public double Value { get; set; }
        public double Percentage { get; set; }
        public List<OverdueSlabAccounts> Accounts { get; set; }
    }

    public class OverdueSlabAccounts
    {
        public string AccountId { get; set; }
        public string AccountName { get; set; }
        public string SalesCode { get; set; }
        public string Value { get; set; }
    }


void Main(){
    List<OverdueModel> overdues = new List<OverdueModel>();
    List<OverdueSlabAccounts> accounts1 = new List<OverdueSlabAccounts>();
    List<OverdueSlabAccounts> accounts2 = new List<OverdueSlabAccounts>();
    List<OverdueSlabAccounts> accounts3 = new List<OverdueSlabAccounts>();

    //For T3
    accounts1.Add(new OverdueSlabAccounts()
        {
            AccountId = "JKB1",
            AccountName = "JKB1",
            SalesCode = "JKB",
            Value = "500"
        });

    accounts1.Add(new OverdueSlabAccounts()
        {
            AccountId = "JKB2",
            AccountName = "JKB2",
            SalesCode = "JKB",
            Value = "500"
        });

    overdues.Add(new OverdueModel()
    {
        Slab = "T3",
        Value = 1000,
        Percentage = 0,
        Accounts= accounts1
    });

    //For T4
    accounts2.Add(new OverdueSlabAccounts()
        {
            AccountId = "JKB1",
            AccountName = "JKB1",
            SalesCode = "JKB",
            Value = "1000"
        });

    overdues.Add(new OverdueModel()
    {
        Slab = "T4",
        Value = 1000,
        Percentage = 0,
        Accounts= accounts2
    });

    //For T5
    accounts3.Add(new OverdueSlabAccounts()
        {
            AccountId = "JKB1",
            AccountName = "JKB1",
            SalesCode = "JKB",
            Value = "1000"
        });

    accounts3.Add(new OverdueSlabAccounts()
        {
            AccountId = "JKB2",
            AccountName = "JKB2",
            SalesCode = "JKB",
            Value = "500"
        });

    accounts3.Add(new OverdueSlabAccounts()
        {
            AccountId = "JKB3",
            AccountName = "JKB3",
            SalesCode = "JKB",
            Value = "500"
        });

    overdues.Add(new OverdueModel()
    {
        Slab = "T5",
        Value = 2000,
        Percentage = 0,
        Accounts= accounts3
    });

    //Show the Current Data
    overdues.Dump();

    var result = overdues.Where(a=>a.Accounts.Any(b=>b.AccountId.Equals("JKB2")));

    result.Dump();


}

Answer 1

此过滤器是正确的，因为它返回了具有记录的{ }实例；问题是您只需要内部OverdueModel的过滤部分。如果假设我们不想更改所有对象，则需要为包含那些已过滤帐户的新模型创建一个投影。也许像这样：

.Accounts

尽管有很多替代方案是可能的。例如，更扁平的模型将是：

var results = from outer in overdues
                where outer.Accounts.Any(b => b.AccountId == "JKB2")
                let filtered = outer.Accounts.FindAll(b => b.AccountId == "JKB2")
                select (Record: outer, Accounts: filtered);

Answer 2

我相信您正在寻找的是LINQ中的SelectMany运算符，该运算符可将一系列的集合弄平。

所以请尝试以下

var result = overdues.SelectMany(a=>a.Accounts).Where(a=>a.AccountId.Equals("JKB2"))

从列表<T>的列表<T>中过滤

2 个答案: