我在asp.net 2005 c#中使用GridView
控件。
如何从GridView
删除特定行。
我写了以下代码。但它不起作用......
DataRow dr = dtPrf_Mstr.NewRow();
dtPrf_Mstr.Rows.Add(dr);
GVGLCode.DataSource = dtPrf_Mstr;
GVGLCode.DataBind();
int iCount = GVGLCode.Rows.Count;
for (int i = 0; i <= iCount; i++)
{
GVGLCode.DeleteRow(i);
}
GVGLCode.DataBind();
答案 0 :(得分:18)
您正在从gridview中删除该行,但您将再次调用databind,这只是将gridview刷新到原始数据源所在的状态。
从数据源中删除它,然后数据绑定,或数据绑定并从gridview中删除它而不进行重新数据绑定。
答案 1 :(得分:12)
您正在从gridview中删除该行,然后将其重新绑定到数据源(仍包含该行)。从数据源中删除行,或者之后不重新绑定gridview。
答案 2 :(得分:4)
默认答案是从您使用的任何集合中删除项目作为GridView的数据源。
如果该选项不合适,那么我建议您使用GridView的RowDataBound
事件有选择地将行的e.Row
)Visible
属性设置为false。
答案 3 :(得分:2)
using System;
using System.Configuration;
using System.Data;
using System.Linq;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.HtmlControls;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Xml.Linq;
using System.Data.SqlClient;
public partial class Default3 : System.Web.UI.Page
{
DataTable dt = new DataTable();
DataSet Gds = new DataSet();
// DataColumn colm1 = new DataColumn();
//DataColumn colm2 = new DataColumn();
protected void Page_Load(object sender, EventArgs e)
{
dt.Columns.Add("ExpId", typeof(int));
dt.Columns.Add("FirstName", typeof(string));
}
protected void BtnLoad_Click(object sender, EventArgs e)
{
// gvLoad is Grid View Id
if (gvLoad.Rows.Count == 0)
{
Gds.Tables.Add(tblLoad());
}
else
{
dt = tblGridRow();
dt.Rows.Add(tblRow());
Gds.Tables.Add(dt);
}
gvLoad.DataSource = Gds;
gvLoad.DataBind();
}
protected DataTable tblLoad()
{
dt.Rows.Add(tblRow());
return dt;
}
protected DataRow tblRow()
{
DataRow dr;
dr = dt.NewRow();
dr["Exp Id"] = Convert.ToInt16(txtId.Text);
dr["First Name"] = Convert.ToString(txtName.Text);
return dr;
}
protected DataTable tblGridRow()
{
DataRow dr;
for (int i = 0; i < gvLoad.Rows.Count; i++)
{
if (gvLoad.Rows[i].Cells[0].Text != null)
{
dr = dt.NewRow();
dr["Exp Id"] = gvLoad.Rows[i].Cells[1].Text.ToString();
dr["First Name"] = gvLoad.Rows[i].Cells[2].Text.ToString();
dt.Rows.Add(dr);
}
}
return dt;
}
protected void btn_Click(object sender, EventArgs e)
{
dt = tblGridRow();
dt.Rows.Add(tblRow());
Session["tab"] = dt;
// Response.Redirect("Default.aspx");
}
protected void gvLoad_RowDeleting(object sender, GridViewDeleteEventArgs e)
{
dt = tblGridRow();
dt.Rows.RemoveAt(e.RowIndex);
gvLoad.DataSource = dt;
gvLoad.DataBind();
}
}
答案 4 :(得分:1)
我的解决方案:
protected void GridView1_RowDeleting(object sender, GridViewDeleteEventArgs e)
{
myobj.myconnection();// connection created
string mystr = "Delete table_name where water_id= '" + GridView1.DataKeys[e.RowIndex].Value + "'";// query
sqlcmd = new SqlCommand(mystr, myobj.mycon);
sqlcmd.ExecuteNonQuery();
fillgrid();
}
答案 5 :(得分:0)
从表dtPrf_Mstr中删除行,而不是从网格视图中删除。
答案 6 :(得分:0)
如何从datagridview中删除
1.按id列号查询删除 2.type
tabletableadaptor.delete
query(datagridwiewX1.selectedrows[0].cell[0].value.tostring);
答案 7 :(得分:0)
请试试这个代码.....
DataRow dr = dtPrf_Mstr.NewRow();
dtPrf_Mstr.Rows.Add(dr);
GVGLCode.DataSource = dtPrf_Mstr;
GVGLCode.DataBind();
int iCount = GVGLCode.Rows.Count;
for (int i = 0; i < iCount; i++)
{
GVGLCode.Rows.Remove(GVGLCode.Rows[i]);
}
GVGLCode.DataBind();