Question

我是Java新手。如何在2D矩阵中找到对角线的总和（看起来像/）？

假设矩阵看起来像这样：

4 6 7
2 4 7 
5 2 7

对角线的总和（看起来像\）是15（4 + 4 + 7）。这是我对角线的代码：

public static int Diagonal(int m[][]) { 
    int sum = 0;
    for(int row = 0; row < m[0].length; row++) {
        sum += m[row][row];
    }
    return sum; 
}

如何找到另一个看起来像（/）的对角线之和？

Answer 1

您可以使用此代码

public static int Diagonal2(int m[][]) {   
    int sum=0;
    for(int row = 0; row < m[0].length; row++) {
        sum += m[row][m.length - row - 1];
    }
    return sum; 
}

Answer 2

喜欢做

public class Main {
    public static void main(String[] args) {
        int[][] matrix = { { 4, 6, 7 }, { 2, 4, 7 }, { 5, 2, 7 } };
        StringBuilder sb = new StringBuilder();
        int sum = sumDiagonal(matrix, sb);
        sb.deleteCharAt(sb.length() - 1);
        System.out.println("The sum of the diagonal is " + sum + " (" + sb + ")");
    }

    public static int sumDiagonal(int m[][], StringBuilder sb) {
        int sum = 0;
        for (int row = 0; row < m[0].length; row++) {
            sum += m[row][m[0].length - row - 1];
            sb.append(m[row][m[0].length - row - 1] + "+");
        }
        return sum;
    }
}

输出

The sum of the diagonal is 16 (7+4+5)

如何在2D矩阵中找到对角线的总和？

2 个答案: