Question

我需要通过 POST 将以下 JSON数组发送到我们的服务器：

task:{"id":"123","list":"456","done":1,"done_date":1305016383}

我尝试使用 JSON库，但我在某种程度上愚蠢地使用它。我甚至试图自己建立POST-String，但也失败了：

NSString *post = @"task='{id:123,list:456,done:1,done_date:1305016383}'";

NSMutableURLRequest *request=[NSMutableURLRequest requestWithURL:url 
                                               cachePolicy:NSURLRequestReloadIgnoringCacheData    
                                            timeoutInterval:30];

[request setHTTPMethod:@"POST"];    
[request setHTTPBody:[post dataUsingEncoding:NSUTF8StringEncoding]];
....

你能帮帮我吗？ json'ed POST字符串对我来说足够了:)）

Answer 1

所以这可能是您要问的问题，也可能不是，但您的JSON字符串形式不正确。 JSON格式的“任务”数组如下所示：

NSString *post = @"{"task":[{"id":"123","list":"456","done":1,"done_date":1305016383}]}";

我只是在尝试将类似的情况发布到PHP服务器上，我在网上找不到任何关于它的问题，但如果我发布相同的数据，这就是我不得不做的事情：

NSString *post = @"task[0][id]=123&task[0][list]=456&task[0][done]=1&task[0][done_date]=1305016383&";

NSMutableURLRequest *request=[NSMutableURLRequest requestWithURL:url 
                                           cachePolicy:NSURLRequestReloadIgnoringCacheData    
                                        timeoutInterval:30];

[request setHTTPMethod:@"POST"];    
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:[post dataUsingEncoding:NSUTF8StringEncoding]];
...

祝你好运！

Answer 2

这就是我处理它的方式：

-(void)imageFactory:(NSDictionary*)postJSON
{
    // Convert the JSON string to Data to be sent.
    NSData* postData = [[postJSON JSONRepresentation] dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
    NSMutableURLRequest* request = [[NSMutableURLRequest alloc] init];
    [request setURL:[NSURL URLWithString:[URLManager imageFactory]]];
    [request setHTTPMethod:@"POST"];
    [request setValue:[NSString stringWithFormat:@"%d", [postData length]] forHTTPHeaderField:@"Content-Length"];
    // IMPORTANT MAKE SURE YOU ADD THIS LINE SO THE SERVER KNOWS WHAT ITS GETTING
    [request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
    [request setHTTPBody:postData];

    // Add some nice handlers so you know what you got from the server
    NSURLResponse* response;
    NSHTTPURLResponse* httpResponse;
    NSError* error;
    NSData* responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
    NSString* stringResponse = [[NSString alloc] initWithData:responseData encoding:NSASCIIStringEncoding];

    httpResponse = (NSHTTPURLResponse*) response;
    int statuscode = [httpResponse statusCode];

    if (statuscode == 200)
    {
        log4Debug(@"ImageFactory Response Successful, Retrieving image");
        // Handle the response here if needed
    }
    else
    {
        log4Error(@"ImageFactory Response Failed: %@", stringResponse);
        // Show some form of alert here if needed
    }
    // release all objects saved to memory
    [request release];
    request = nil;
    [stringResponse release];
    stringResponse = nil;
}

我的json是一个看起来像这样的字符串 {“user”：1337，“title”：“some title”，“itemKeys”：[1,1,1,1,1]}

Answer 3

我认为问题不在于方法，而在于您尝试发布的字符串。试试这个：

NSString *post = @"\"task\":{\"id\":\"123\",\"list\":\"456\",\"done\":1,\"done_date\":1305016383}";

换句话说：用引号进行试验。

您使用的是什么JSON库？

iPhone通过POST发送Json Array

3 个答案: