我正在尝试在python中创建一个空白的多索引,但是内部级别(#of基金)并没有按照我想要的方式出现。每个VY应该都有完整的Fund1-15系列,但是输出似乎是1:1。有什么想法吗?
例如,我需要: VY1 =外部索引 ->基金#1,基金#2,基金#3,...基金#15 =内部指数 VY2 ->基金#1,基金#2,基金#3,...基金#15 =内部指数 等等
使用下面的错误代码,它只是在这样做: VY1基金1 VY2基金2 VY3基金3 等等
outside = ['VY1','VY2','VY3','VY4','VY5','VY6','VY7','VY8','VY9','VY10','VY11','VY12','VY13','VY14','VY15']
inside = ['#fund1','#fund2','#fund3','#fund4','#fund5','#fund6','#fund7','#fund8','#fund9','#fund10','#fund11','#fund12','#fund13','#fund14','#fund15']
hier_index = list(zip(outside,inside))
hier_index = pd.MultiIndex.from_tuples(hier_index)
df = pd.DataFrame(0,index=hier_index,columns=['TVPI series'])
答案 0 :(得分:0)
如果我对您的理解正确,那么您想创建分层的多索引:
outside = ['VY1','VY2','VY3','VY4','VY5','VY6','VY7','VY8','VY9','VY10','VY11','VY12','VY13','VY14','VY15']
inside = ['#fund1','#fund2','#fund3','#fund4','#fund5','#fund6','#fund7','#fund8','#fund9','#fund10','#fund11','#fund12','#fund13','#fund14','#fund15']
hier_index = []
for k in outside:
for l in inside:
hier_index.append( (k, l) )
hier_index = pd.MultiIndex.from_tuples(hier_index, names=['first', 'second'])
df = pd.DataFrame(0,index=hier_index,columns=['TVPI series'])
print(df)
打印:
TVPI series
first second
VY1 #fund1 0
#fund2 0
#fund3 0
#fund4 0
#fund5 0
... ...
VY15 #fund11 0
#fund12 0
#fund13 0
#fund14 0
#fund15 0
[225 rows x 1 columns]