Question

如何使用split和substring和foreach处理数组以输出以下信息。

我尝试使用split和substring。但仍然无法正常工作。谢谢。

$item=$item.ToString() 
$driveID=$item.Substring(0,26) 
$ID=($driveID.Split(":")[-1]).trim()
$status=$item.Substring(27,$item.Length-1-27)
$stauts1=($status.split(",")[-1]).trim()

输入【数组】：

physicaldrive 1I:1:9 (port 1I:box 1:bay 9, SAS HDD, 900 GB, OK)
physicaldrive 1I:1:10 (port 1I:box 1:bay 10, SAS HDD, 900 GB, OK)
physicaldrive 1I:1:11 (port 1I:box 1:bay 11, SAS HDD, 2.4 TB, OK, spare)
physicaldrive 1I:1:12 (port 1I:box 1:bay 12, SAS HDD, 900 GB, OK, shared spare)

预期输出：

DriveID DriveStatus
9  OK
10 OK
11 OK
12 OK

Answer 1

以下假设DriveID是单词bay之后的数字。该代码将捕获命名的捕获组，并使用它们来创建PSCustomObject。然后将其发送到$DriveInfo集合，并最终显示在屏幕上。此时，您可以轻松导出它。 [咧嘴]

#region >>> fake reading in a text file
#    in real life, use Get-Content
$InStuff = @'
physicaldrive 1I:1:9 (port 1I:box 1:bay 9, SAS HDD, 900 GB, OK)
physicaldrive 1I:1:10 (port 1I:box 1:bay 10, SAS HDD, 900 GB, OK)
physicaldrive 1I:1:11 (port 1I:box 1:bay 11, SAS HDD, 2.4 TB, OK, spare)
physicaldrive 1I:1:12 (port 1I:box 1:bay 12, SAS HDD, 900 GB, OK, shared spare)
'@ -split [System.Environment]::NewLine
#endregion >>> fake reading in a text file


$DriveInfo = $InStuff.ForEach({
    $Null = $_ -match '^.+:bay (?<DriveID>\d+), .+b, (?<Status>.+).+$'
    [PSCustomObject]@{
        DriveID = $Matches.DriveID
        Status = $Matches.Status.Split(',')[0]
        }
    })

$DriveInfo

输出...

DriveID Status
------- ------
9       OK    
10      OK    
11      OK    
12      OK

如何使用split和substring和foreach处理数组

1 个答案: