我有疑问 如何向现有数组中插入值,我对结果的解释就像:
Array
(
[id] => 11
[title] => Lorem ipsum
[view] => 3445
)
但是我所做的是:
<?php
$newVideo = [
'id'=>'11',
'title'=>'Lorem ipsum'
];
$view = '3445';
$newVideo[] = ['view'=>$view];
print_r($newVideo);
我的结果是:
Array
(
[id] => 11
[title] => Lorem ipsum
[0] => Array
(
[view] => 3445
)
)
更新问题:就我而言,我有复杂的foreach 在每个foreach中,我想将值存储到变量数组中,如下所示:
$newVideo = array();
foreach ($videos['items'] as $v){
$id = $v['snippet']['resourceId']['videoId'];
$title = $v['snippet']['title'];
$newVideo[] = [ "id" => $id ,"title" => $title];
$ newVideo是具有['id']和['title']的,我也想存储['view'],但是我必须先使用foreach函数才能从['id']获取视图数据我的foreach函数获取视图的代码如下:
$funcvid = array();
foreach($newVideo as $id){
$ids = $id['id'];
$vidview = YtJson('apilink', $ids, '');
array_push($funcvid, $vidview);
}
我获得了视频统计信息,因此我可以从该函数中获取视图数据,因此我再次foreach来使用以下代码存储视图数据值:
foreach($funcvid as $f){
foreach ($f['items'] as $h){
$view = $h['statistics']['viewCount'];
}
$newVideo['view'] = $view;
}
但是对于最后一次foreach,我无法将值存储到$ newVideo ['view'],它不会发生变化,如果array是2维的,我就成功了,但是我的研究是array是1维的
答案 0 :(得分:0)
$newVideo
是二维数组。您需要为第一个维度建立索引才能到达关联的内部数组。
foreach($funcvid as $i => $f){
foreach ($f['items'] as $h){
$view = $h['statistics']['viewCount'];
}
$newVideo[$i]['view'] = $view;
}
但是您不需要3个不同的循环,您可以在一个循环中完成所有操作。
<?php
$newVideo = array();
foreach ($videos['items'] as $v){
$id = $v['snippet']['resourceId']['videoId'];
$title = $v['snippet']['title'];
$vidview = YtJson('apilink', $ids, '');
foreach ($vidview['items'] as $h) {
$view = $h['statistics']['viewCount'];
}
$newVideo[] = [ "id" => $id ,"title" => $title, 'view' => $view];
}