大家好我正在尝试使用http://search.twitter.com/search.json来提取某些用户的Feed。它似乎与大多数工作，但我似乎无法拉取justinbieber的推特提示我一直得到空的结果
我可以毫无疑问地拉扯
http://twitter.com/#!/wilw
http://search.twitter.com/search.json?q=from:wilw
{"results":[{"from_user_id_str":"20300","profile_image_url":"http://a0.twimg.com/profile_images/421184034/qc_avatar_flip_normal.png","created_at":"Wed, 11 May 2011 03:23:19 +0000","from_user":"wilw","id_str":"68154189968191488","metadata":{"result_type":"recent"},"to_user_id":null,"text":"That Joke Isn't Funny Anymore #ValleySmiths (Thank you for your indulgence, and my apologies. Here endeth the flood.)","id":68154189968191488,"from_user_id":20300,"geo":null,"iso_language_code":"en","to_user_id_str":null,"source":"<a href="http://twitter.com/">web</a>"}],"max_id":68154189968191488,"since_id":0,"refresh_url":"?since_id=68154189968191488&q=from%3Awilw","next_page":"?page=2&max_id=68154189968191488&rpp=1&q=from%3Awilw","results_per_page":1,"page":1,"completed_in":0.017642,"since_id_str":"0","max_id_str":"68154189968191488","query":"from%3Awilw"}
但是当谈到justinbieber（它的工作对不起）
http://twitter.com/#!/JUSTINBIEBER
http://search.twitter.com/search.json?q=from:JUSTINBIEBER
我得到[]结果
{"results":[],"max_id":68133219333189632,"since_id":0,"refresh_url":"?since_id=68133219333189632&q=from%3AJUSTINBIEBER","results_per_page":1,"page":1,"completed_in":0.222307,"since_id_str":"0","max_id_str":"68133219333189632","query":"from%3AJUSTINBIEBER"}
答案 0 :(得分：1)
如果您只是收到特定用户的推文，则应使用GET statues/user_timeline方法而不是搜索API。
https://api.twitter.com/1/statuses/user_timeline.json?screen_name=JUSTINBIEBER