Question

我想按值对嵌套字典排序，按另一个值对余数进行排序，再按另一个值对余数进行排序。我有三个条件。我要为三个中的两个分配reverse = True，但是对于第三个条件，我想要分配reverse = False。如何使用reversed和lambda？这是一段代码：

Map

k [1] [“ W”]和k [1] [“ PKT”]必须相反，而k [1]不能相反。

Answer 1

我找不到更短的内容，所以我建议采取以下解决方案：

dict_punkty={'Jan': {'W': 1, 'PKT': 25}, 'Artur': {'W': 1, 'PKT': 20}, 'Karol': {'W': 0, 'PKT': 10}}

# Put key names in a list sorted in reverse order
names = sorted(dict_punkty.keys(), reverse=True)

# Put names and their order in a temporary dictionary
names = {name: i for i, name in enumerate(names)}

# Put the data in a list of tuples replacing key names with order numbers
result = [(names[k[0]], k[1]) for k in dict_punkty.items()]

# Sort the list of tuples
result = sorted(result, key=lambda k: (k[1]["W"], k[1]["PKT"], k[0]), reverse=True)

# Reverse names/orders as keys/values in the temporary dictionary
names = {i: name  for name, i in names.items()}

# Get the final result by replacing the order numbers with key names
result = [(names[k[0]], k[1]) for k in result]

print(result)

如何对嵌套字典进行排序？

1 个答案: