字符串列排序Sql select

Question

我在sql查询中遇到问题，正在向我返回混乱的结果，我想指导您在逗号前输入数字，我不知道您是否可以按照示例进行操作：

SELECT responsaveis FROM public.pasrem_view where seqalu = 444111;

结果：

"DIOGO LUIZ BORDON DE SOUZA-89812239120-FILIACAO2, DIOGO LUIZ BORDON DE SOUZA-89812239120-FILIACAO2,DIOGO LUIZ BORDON DE SOUZA-89812239120-FILIACAO2, DIOGO LUIZ BORDON DE SOUZA-89812239120-FILIACAO2,LILIANA LETICIA CARVALHO THEODORO-00163264155-FILIACAO1,DIOGO LUIZ BORDON DE SOUZA-89812239120-FILIACAO2, DIOGO LUIZ BORDON DE SOUZA-89812239120-FILIACAO2,DIOGO LUIZ BORDON DE SOUZA-89812239120-FILIACAO2,DIOGO LUIZ BORDON DE SOUZA-89812239120-FILIACAO2"

我希望您像这样回到我身边

"LILIANA LETICIA CARVALHO THEODORO-00163264155-FILIACAO1,DIOGO LUIZ BORDON DE SOUZA-89812239120-FILIACAO2,DIOGO LUIZ BORDON DE SOUZA-89812239120-FILIACAO2,DIOGO LUIZ BORDON DE SOUZA-89812239120-FILIACAO2,DIOGO LUIZ BORDON DE SOUZA-89812239120-FILIACAO2,DIOGO LUIZ BORDON DE SOUZA-89812239120-FILIACAO2,DIOGO LUIZ BORDON DE SOUZA-89812239120-FILIACAO2,DIOGO LUIZ BORDON DE SOUZA-89812239120-FILIACAO2,DIOGO LUIZ BORDON DE SOUZA-89812239120-FILIACAO2"

请记住，这只是一个结果，并且该字段是由“，”分隔的字符串。

示例：https://dbfiddle.uk/?rdbms=postgres_12&fiddle=cdf790d74b053ef8289e428eed0bd62e

Answer 1

您需要首先将元素嵌套到行中（本质上是“即时”规范化数据模型），然后可以将其聚合回排序后的字符串：

SELECT string_agg(trim(t.element), ',' order by t.element desc)
FROM public.pasrem_view 
  cross join unnest(string_to_array(responsaveis, ',')) as t(element)
where seqalu = 444111;

Online example

Answer 2

您的问题是指逗号前的数字。但是样本数据中没有逗号。对于您的结果，降序排序将起作用：

SELECT responsaveis
FROM public.pasrem_view 
WHERE seqalu = 444111
ORDER BY responsaveis DESC;