Question

我已经使用php从日志文件中解析了日志，并将这些行推送到了数组中。

[2020-01-21 18:01:23] local.INFO: Backup success
[2020-01-21 18:11:03] local.DEBUG: aid=1 bac=2343
[2020-01-21 18:21:29] production.CRITICAL:send failed
[2020-01-21 18:51:01] production.WARNING:limit 7/9 reached

如何从每一行中更有效地获得期望的输出？

$final = [];
foreach($lines as $line){
    //best way to parse data to $date, $env, $type, $message from $line variable?

    $arr = [
        'date'=> $date,
        'env'=> $env,
        'type'=> $type,
        'message'=> $message
    ];
    array_push($final, $arr);
}

期望

[
    {
        "date":"2020-01-21 18:01:23",
        "env":"local",
        "type":"INFO",
        "message":"Backup success"
    },
    {
        "date":"2020-01-21 18:21:29",
        "env":"production",
        "type":"CRITICAL",
        "message":"send failed"
    },
    ...
    ...
]

Answer 1

尝试此版本。

$re = '/^\[(?<date>.*)\]\s(?<env>\w+)\.(?<type>\w+):(?<message>.*)/m';

$str = '[2020-01-21 18:01:23] local.INFO: Backup success
[2020-01-21 18:11:03] local.DEBUG: aid=1 bac=2343
[2020-01-21 18:21:29] production.CRITICAL:send failed
[2020-01-21 18:51:01] production.WARNING:limit 7/9 reached';

preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);

// Print the entire match result
var_dump($matches);

// Print json string
echo json_encode($matches, JSON_PRETTY_PRINT);

Answer 2

希望这可以解决您对问题的回答：）

$lines = '[2020-01-21 18:01:23] local.INFO: Backup success';
$arr = explode('] ', $lines);
$arr1 = explode(': ', $arr[1]);
$arr2 = explode('.', $arr1[0]);
$arr[0] = str_replace("[","",$arr[0]);
echo 'date = ' . $arr[0];
echo '<br>';
echo 'env = ' .$arr2[0];
echo '<br>';
echo 'type = ' .$arr2[1];
echo '<br>';
echo 'message = ' .$arr1[1];
echo '<br>';

Answer 3

爆炸，子字符串，修剪和数组解构的混合：

$final = [];
foreach ($lines as $line) {
    [$envType, $message] = explode(':', substr($line, 22));
    [$env, $type] = explode('.', $envType);

    $final[] = [
        'date'    => substr($line, 1, 19),
        'env'     => $env,
        'type'    => $type,
        'message' => trim($message)
    ];
}

$jsonFormat = json_encode($final, JSON_PRETTY_PRINT|JSON_UNESCAPED_SLASHES);

正则表达式解析PHP日志文件

3 个答案: