Question

我有JSON列，其中包含JSON数组。我的方案是获取所有记录，其中url的值是 '"example.com/user1"'存在。我无法为此操作编写查询。

Record1
 [
    {
        "id": "1",
        "firstname": "user1",
        "url": "example.com/user1"
    },
    {
        "id": "2",
        "firstname": "user2",
        "url": "example.com/user2"
    }
]
Record2
     [
        {
            "id": "1",
            "firstname": "user3",
            "url": "example.com/user3"
        },
        {
            "id": "2",
            "firstname": "user2",
            "url": "example.com/user2"
        }
    ]
......
......
......
Record10
     [
        {
            "id": "1",
            "firstname": "user10",
            "url": "example.com/user10"
        },
        {
            "id": "2",
            "firstname": "user1",
            "url": "example.com/user1"
        }
    ]

我运行的查询是：

Select internal_id from users_dummy where JSON_EXTRACT(user_friends, '$[0].url') = "example.com/user1" or JSON_EXTRACT(user_friends, '$[1].url') = "example.com/user1";

所以o / p是： Record1, Record10

这是在记录中搜索值的正确方法吗？预先感谢。

Answer 1

您可以像这样使用JSON_SEARCH：

SELECT * 
FROM users_dummy 
WHERE JSON_SEARCH(user_friends, 'one', 'example.com/user1', NULL, '$[*].url') IS NOT NULL

demo on dbfiddle.uk

如果使用的是对象而不是数组，则可以使用以下解决方案：

SELECT * 
FROM users_dummy 
WHERE JSON_SEARCH(user_friends, 'one', 'example.com/user1', NULL, '$.*.url') IS NOT NULL

demo on dbfiddle.uk

在MySQL中检索JSON数组内的Json数据的值

1 个答案: