Question

给出一个像这样的Python字符串：

location_in = 'London, Greater London, England, United Kingdom'

我想将其转换为这样的列表：

location_out = ['London, Greater London, England, United Kingdom',
                'Greater London, England, United Kingdom',
                'England, United Kingdom',
                'United Kingdom']

换句话说，给定逗号分隔的字符串（location_in），我想将其复制到列表（location_out）并逐渐删除它，每次删除第一个单词/短语

我是一个Python新手。写这个的好方法有什么想法吗？感谢。

Answer 1

location_in  = 'London, Greater London, England, United Kingdom'
locations    = location_in.split(', ')
location_out = [', '.join(locations[n:]) for n in range(len(locations))]

Answer 2

有很多方法可以做到这一点，但这里有一个：

def splot(data):
  while True:
    yield data
    pre,sep,data=data.partition(', ')
    if not sep:  # no more parts
      return

location_in = 'London, Greater London, England, United Kingdom'
location_out = list(splot(location_in))

更有悖常理的解决方案：

def stringsplot(data):
  start=-2               # because the separator is 2 characters
  while start!=-1:       # while find did find
    start+=2             # skip the separator
    yield data[start:]
    start=data.find(', ',start)

Answer 3

这是一个有效的工作：

location_in = 'London, Greater London, England, United Kingdom'
loci = location_is.spilt(', ') # ['London', 'Greater London',..]
location_out = []
while loci:
  location_out.append(", ".join(loci))
  loci = loci[1:] # cut off the first element
# done
print location_out

Answer 4

>>> location_in = 'London, Greater London, England, United Kingdom'
>>> location_out = []
>>> loc_l = location_in.split(", ")
>>> while loc_l:
...     location_out.append(", ".join(loc_l))
...     del loc_l[0]
... 
>>> location_out
['London, Greater London, England, United Kingdom', 
 'Greater London, England, United Kingdom', 
 'England, United Kingdom', 
 'United Kingdom']
>>>

Python - 将逗号分隔的字符串转换为缩减字符串列表

4 个答案: