尽管here记录了Pydantic的ORM模式,但遗憾的是,没有有关别名使用的文档。
如果pydantic模型定义了别名,如何使用from_orm
?
如果存在别名,看来from_orm
工厂会忘记所有非别名。 -请参阅以下错误消息和相应的代码。那是错误还是功能?
以下代码段意外失败,并显示验证错误:
pydantic.error_wrappers.ValidationError:1个用于SimpleModel的验证错误
threeWordsId
必填字段(类型= value_error.missing)
from sqlalchemy import Column, String
from sqlalchemy.ext.declarative import declarative_base
from pydantic import BaseModel, Field
Base = declarative_base()
class SimpleOrm(Base):
__tablename__ = 'simples'
three_words_id = Column(String, primary_key=True)
class SimpleModel(BaseModel):
three_words_id: str = Field(..., alias="threeWordsId")
class Config:
orm_mode=True
simple_orm = SimpleOrm(three_words_id='abc')
simple_oops = SimpleModel.from_orm(simple_orm)
答案 0 :(得分:2)
在配置中使用allow_population_by_field_name = True。
喜欢
from sqlalchemy import Column, String
from sqlalchemy.ext.declarative import declarative_base
from pydantic import BaseModel, Field
Base = declarative_base()
class SimpleOrm(Base):
__tablename__ = 'simples'
three_words_id = Column(String, primary_key=True)
class SimpleModel(BaseModel):
three_words_id: str = Field(..., alias="threeWordsId")
class Config:
orm_mode = True
allow_population_by_field_name = True
# allow_population_by_alias = True # in case pydantic.version.VERSION < 1.0
simple_orm = SimpleOrm(three_words_id='abc')
simple_oops = SimpleModel.from_orm(simple_orm)
print(simple_oops.json()) # {"three_words_id": "abc"}
print(simple_oops.json(by_alias=True)) # {"threeWordsId": "abc"}
from fastapi import FastAPI
app = FastAPI()
@app.get("/model", response_model=SimpleModel)
def get_model():
# results in {"threeWordsId":"abc"}
return SimpleOrm(three_words_id='abc')