Question

我有一个类似（简化）的查询：

SELECT 
    JSON_QUERY(r.SerializedData, '$.Values') AS [Values] 
FROM 
    <TABLE> r 
WHERE ...

结果是这样的：

{ "201902":121, "201903":134, "201904":513 }

如何在SQL中将其更改为：

{ "2019-02-01":121, "2019-03-01":134, "2019-04-01":513 }

在年份之后（4位数字）意味着添加“-”并以“ -01”结束键。

Answer 1

对于SQL2017及更高版本，您可以使用renaming a key的示例（这可能有点麻烦，并且在键重复的情况下可能无法正常工作）

declare @j1 nvarchar(max);
select @j1 = N'{"201902":121, "201902":145, "201903":134, "201904":513}';

select @j1 as before;

select @j1 = JSON_MODIFY(JSON_MODIFY(@j1, concat('$."', left(a.[key], 4), '-', right(a.[key], 2), '-01"'), CAST(a.value AS int)), concat('$."', a.[key], '"'), null)
from openjson(@j1) as a;

select @j1 as after, isjson(@j1);

或使用简单的REPLACE（）将json作为字符串处理

declare @j2 nvarchar(max);
select @j2 = N'{"201902":121, "201902":145, "201903":134, "201904":513}';

select @j2 as before;

select @j2 = replace(@j2, a.[key], concat(left(a.[key], 4), '-', right(a.[key], 2), '-', '01'))
--if keys appear as values...
--replace(@j2, concat('"', a.[key], '"'), concat('"', stuff(a.[key],5, 0, '-'), '-01"'))
from openjson(@j2) as a;

select @j2 as after, isjson(@j2);

SQL Server：如何更新json数组内的所有键

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