从使用类名作为输入的方法返回二维数组

时间:2020-02-14 20:40:39

标签: java multidimensional-array

我在行return gameBoard;上收到错误消息“类型不匹配无法从String [] []转换为GameBoard [] []”。如何更改此公共类GameBoard,以便能够返回2D数组中的字符串值? (我不想将方法的返回类型更改为String [] [])


public class GameBoard {

    String[][] gameBoard;


    /**
     * Constructor
     */

    public GameBoard() {
        gameBoard = new String[4][5];
    }   

    /**
     * Filling the playable board with Strings
     * @return
     */

     public GameBoard[][] fillGameBoard() {

        gameBoard[0][0] = new String("1");
        gameBoard[0][1] = new String("2");
        gameBoard[0][2] = new String("3");
        gameBoard[0][3] = new String("4");
        gameBoard[0][4] = new String("5");
        gameBoard[1][0] = new String("6");
        gameBoard[1][1] = new String("7");
        gameBoard[1][2] = new String("8");
        gameBoard[1][3] = new String("9");
        gameBoard[1][4] = new String("10");
        gameBoard[2][1] = new String("11");
        gameBoard[2][2] = new String("12");
        gameBoard[2][3] = new String("13");
        gameBoard[3][1] = new String("14");
        gameBoard[3][2] = new String("15");
        gameBoard[3][3] = new String("16");



        return gameBoard;

    }```


1 个答案:

答案 0 :(得分:1)

之所以会发生这种情况,是因为您告诉编译器您将返回GameBoard[][]类型,但实际上是返回String[][]类型,因此您可能会以与命名类相同的方式命名成员变量而感到困惑。您可能想为其命名一个不太混乱的名称。

通常,为GameBoard定义类的方法很好,因为您稍后可能想对它执行不同的操作,例如move()从一个单元格到另一个单元格或其他内容的内容。但是请记住,您的“客户端类”不知道您的类的内部外观,因此您不能仅将GameObject存储为String[][],反之亦然

这是您的课程的一个示例,其中包含一些有关如何声明使用GameBoard的变量的注释以及一些建议: (这将无法正常工作,您必须删除不想使用的方法,因为它们在返回类型中不匹配

public class GameBoard {

    String[][] gameBoard;

    /**
     * Constructor
     */
    public GameBoard() {
        gameBoard = new String[4][5];
    }   

    // Approach 1
     public void fillGameBoard() {

        gameBoard[0][0] = "1";
        gameBoard[0][1] = "2";
        gameBoard[0][2] = "3";
        gameBoard[0][3] = "4";
        gameBoard[0][4] = "5";
        gameBoard[1][0] = "6";
        gameBoard[1][1] = "7";
        gameBoard[1][2] = "8";
        gameBoard[1][3] = "9";
        gameBoard[1][4] = "10";
        gameBoard[2][1] = "11";
        gameBoard[2][2] = "12";
        gameBoard[2][3] = "13";
        gameBoard[3][1] = "14";
        gameBoard[3][2] = "15";
        gameBoard[3][3] = "16";
    }

    // Approach 2
    // If you really want to go with the way you had your declaration set up
    // GameBoard board = new GameBoard().fillGameBoard();
    // you would have to do this
    public GameBoard fillGameBoard() {
        fillGameBoard();

        return this;
    }

    // Approach 3
    // If you want to do this, you don't need your class at all and your fillGameBoard 
    // has to return a String[][] type. I would recommend against it though,
    // since you are using a highly object oriented language as Java
    public String[][] fillGameBoard() {
        fillGameBoard();

        return gameBoard;
    }

    public static void main(String[] args) {
        // Approach 1
        // I recommend this approach!
        GameBoard board2 = new GameBoard();
        board2.fillGameBoard();

        // Approach 2
        GameBoard board = new GameBoard().fillGameBoard();

        // Approach 3
        String[][] board3 = new GameBoard().fillGameBoard();
    }
}
相关问题