Question

我在服务类中定义了此调用

@POST("enquiries/")
Call<Enquiry> postEnquiry(
        @Header("Authorization") String token,
        @Body RequestBody body
);

这是我在存储库文件中实际调用它时的情况：

RequestBody body = requestBody.build();
    enquiriesService.postEnquiry(token, body).enqueue(new Callback<Enquiry>() {...

在检查传出网络呼叫时，我发现传出请求的正文为空。

如何在请求正文中发送RequestBody对象？

Answer 1

发送是什么意思？您的代码已经发送了一个请求正文和令牌。

您始终可以使用HttpLoggingInterceptor在Logcat https://github.com/square/okhttp/tree/master/okhttp-logging-interceptor中记录您的请求

val apiService: ApiService
        get() = setupInstance().create(ApiService::class.java)

private fun setupInstance(): Retrofit {

        return Retrofit.Builder()
                .baseUrl("BASE_URL")
                .client(createClient())
                .addCallAdapterFactory(CoroutineCallAdapterFactory())
                .addConverterFactory(GsonConverterFactory.create(gson))
                .build()
}

private fun createClient(): OkHttpClient {
        val logging = HttpLoggingInterceptor()
        HttpLoggingInterceptor.Level.BODY

        return OkHttpClient.Builder()
                .connectTimeout(60, TimeUnit.SECONDS)
                .readTimeout(60, TimeUnit.SECONDS)
                .writeTimeout(60, TimeUnit.SECONDS)
                .build()
}

Answer 2

您可以使用Model类发送请求的正文。

例如，

// Task.java
public class Task {  
    private long id;
    private String text;

    public Task(long id, String text) {
        this.id = id;
        this.text = text;
    }
}

// ApiInterface
public interface TaskApi {  
    @POST("/tasks")
    void createTask(@Body Task task);
}

// You can request like this
Task task = new Task(1, "my task title");  
Call<Task> call = taskService.createTask(task);  
call.enqueue(new Callback<Task>() {});

因此，您的请求正文如下

{
    "id": 1,
    "text": "my task title"
}

如何在翻新呼叫中发送请求正文？

2 个答案: