Question

我正在尝试将数据库代码放入函数中。我无法从函数返回结果，因此页面上的所有变量都引发未定义的变量错误。

function fetchVideo($dblink) {
    $viewkey=$_GET['viewkey'];
    $sql = "SELECT * FROM videos WHERE Viewkey='".$viewkey."'";
    $result = mysqli_query($dblink, $sql);
    if (mysqli_num_rows($result) > 0) {
        while($row = mysqli_fetch_assoc($result)) {
                return $key=$row["Viewkey"];
                return $embed=$row["Embed"];
                return $link=$row["Link"];
                return $url=$row["URL"];
                return $categories=explode(";", $row["Categories"]);
                return $rating=$row["Rating"];
                return $username=$row["User_name"];
                return $title=$row["Title"];
                return $tags=str_replace(";","-", explode(",", $row["Tags"]));
                return $duration=intdiv($row["Duration"],60);
                return $thumbnail=$row["Thumbnail"];
        }
    } else {echo 'No Results';}
}

上面的代码在从函数中删除并删除所有“返回”时起作用。我尝试将其作为数组并返回该数组且没有骰子：

    function fetchVideo($dblink) {
        $viewkey=$_GET['viewkey'];
        $sql = "SELECT * FROM videos WHERE Viewkey='".$viewkey."'";
        $result = mysqli_query($dblink, $sql);
        if (mysqli_num_rows($result) > 0) {
            while($row = mysqli_fetch_assoc($result)) {
                $video=array (
                    "key"=>$row["Viewkey"],
                    "embed"=>$row["Embed"],
                    "link"=>$row["Link"],
                    "url"=>$row["URL"],
                    "categories"=>explode(";", $row["Categories"]),
                    "rating"=>$row["Rating"],
                    "username"=>$row["User_name"],
                    "title"=>$row["Title"],
                    "tags"=>str_replace(";","-", explode(",", $row["Tags"])),
                    "duration"=>intdiv($row["Duration"],60),
                    "thumbnail"=>$row["Thumbnail"]
                );
            }
        } else {echo 'No Results';}
        return $video;
    }

我在做什么错了？

Answer 1

要创建一个数组数组：

$video = array() # placed outside of loop and before if statement
if (mysqli_num_rows($result) > 0) {
    while($row = mysqli_fetch_assoc($result)) {
        // add next row to the $video array:
        $video[] = array(
             "key"=>$row["Viewkey"],
              etc.
        );
    }
} else {echo 'No Results';}
return $video;

如何从php函数返回数据库查询的结果？

1 个答案: