Question

以下内容在开发人员控制台中发布为 POST：404 。我猜我的php不正确。我在这里做什么错了？

在JS方面，我正在做

    ........
    user = JSON.stringify(user); // updated Data, want to push to db table blob column
    pushData ();

    function pushData (){
        const ajax = $.ajax({
            method: 'POST',
            url: `./Settings.php`,
            data: {obj_json: JSON.stringify(user) },
            dataType: "json",
            success: function(result) {
                //Write your code here
                console.log("data posted?");
            }
          });
        }
  .....

/Settings.php （使用的类具有有效的数据库连接，我的obj_json是在数据库表中设置为blob的列）。我不太确定如何处理$obj

class Settingz extends \myApp\Data
{

    public function insertBlob($obj, $last_update) {
        $obj = $_POST['obj_json'];

        $sql = "INSERT INTO MY_TABLE(last_update,obj_json) VALUES(:last_update,:obj_json)";
        $stmt = $this->pdo->prepare($sql);

        $stmt->bindParam(':last_update', $last_update);
        $stmt->bindParam(':obj_json', $blob, PDO::PARAM_LOB);

        return $stmt->execute();
    }
  }

Answer 1

使用OCI8，您可以使用临时LOB（请参阅The Underground PHP and Oracle Manual第235页），但是对于PDO_OCI，请使用RETURNING子句，如：

<?php


try {
    $db = new PDO('oci:dbname=localhost/orclpdb1', 'cj', 'welcome');
}
catch (PDOException $e) {
    echo 'Connection failed: ' . $e->getMessage();
    exit;
}

$stmt = $db->prepare("drop table cjblob");
$stmt->execute();

$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

$stmt = $db->prepare("create table cjblob (id number, data blob)");
$stmt->execute();

function do_insert($db, $id, $data)
{
    $stmt = $db->prepare("insert into cjblob (id, data) values (:id, empty_blob()) returning data into :blob");
    $stmt->bindParam(':id', $id);
    $stmt->bindParam(':blob', $blob, PDO::PARAM_LOB);
    $blob = null;
    $db->beginTransaction();
    $stmt->execute();

//  var_dump($blob);  // $blob becomes a stream

    fwrite($blob, $data);
    fclose($blob);
    $db->commit();
}

do_insert($db, 1, str_pad("Z",  40000, "Z"));

// Fetch it back
$stmt = $db->prepare('select data from cjblob where id = ?');
$id = 1;
$stmt->execute(array($id));
$row = $stmt->fetch(PDO::FETCH_ASSOC);
var_dump($row);
var_dump(stream_get_contents($row['DATA']));

?>

将json对象插入oracle db表blob列

1 个答案: